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leva [86]
3 years ago
13

Finding an irrational number between which given pair of numbers supports the idea that irrational numbers are dense

Mathematics
1 answer:
Fittoniya [83]3 years ago
8 0

Answer:

3.33 and 1/3

Step-by-step explanation:

"Dense" here means that there are infinite irrational numbers between two rational numbers. Also, there are infinite rational numbers between two rational numbers. That's the meaning of dense. Actually, that can be apply to all real numbers, there always is gonna be a number between other two.

But, to demonstrate that irrationals are dense, we have to based on an interval with rational limits, because the theorem about dense sets is about rationals, and the dense irrational set is a deduction from it. That's why the best option is 2, because that's an interval with rational limits.

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Simplifying radicals: √196s²
aliya0001 [1]
√196s² = √196 times √s²

s² is the square of 's'
196 is the square of 14
So both can easily come out of the radical.

√196s² = <u>14s</u>

3 0
3 years ago
Solve the inequality: (x+3)(x−4)&lt;−12
melamori03 [73]

Answer:

0<x<1

Step-by-step explanation:

(x+3)(x−4)<−12

FOIL

x^2 -4x+3x -12 <-12

x^2 -x -12 <-12

Add 12 to each side

x^2 -x -12+12 <-12+12

x^2 -x <0

Factor out an x

x(x-1) <0

Using the zero product property

x(x-1) =0

x=0  x-1=0

x=0  x=1

Check the ranges

x<0

x(x-1) <0        

- * - >0

False

0<x<1

x(x-1) <0        

+ * - <0

True

x>1

x(x-1) <0        

+ * + >0

False

3 0
2 years ago
Pls answer urgent. 4 questions only, due today pls help answer
anzhelika [568]

Answer:

ANS: 1 - D

ANS: 2 - B

ANS: 3 - A

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Step-by-step explanation:

8 0
2 years ago
Quadrilateral ABCD is translated 6 units right and 5 units down to create quadrilateral EFGH. Determine the correct orientation
Vlad [161]

Try this suggested option (all the details are in the attachment), the correct orientation is marked with red and green colours.

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6 0
2 years ago
An equation of the line passing through (6,−3) having slope −35 is
Masja [62]
If your given slope is - 35, your equation starts off as y = - 35x + b

Now we plug in the point given and solve for b. 

- 3 = - 35(6) + b
- 3 = - 210 + b
207 = b

So your equation is:
y = - 35x + 207
3 0
3 years ago
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