Answer:
B
Step-by-step explanation:
It's a relationship
Your answer is C. 50t+30m=1500 and 4t+3m=138
325 adult tickets were sold
<em><u>Solution:</u></em>
Let "a" be the number of adult tickets sold
Let "s" be the number of student tickets sold
<em><u>Given that total 706 tickets were sold for the school play</u></em>
Therefore,
number of adult tickets sold + number of student tickets sold = 706
a + s = 706 --------- eqn 1
<em><u>There were 56 more student tickets sold than adult tickets</u></em>
Number of student tickets sold = 56 + number of adult tickets sold
s = 56 + a ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
a + 56 + a = 706
2a + 56 = 706
2a = 706 - 56
2a = 650
a = 325
Thus 325 adult tickets were sold
Theirs no image please post a image of the table
I don't understand what you mean by 'mentally' but anyways, here is how to solve it.
(z−12)(z+12)
=(z+−12)(z+12)
=(z)(z)+(z)(12)+(−12)(z)+(−12)(12)
=z^2+12z−12z−144
=z^2−144
