Answer:
a) 99.93%
b) 99.98%
Explanation:
Given that:
Total population size was only around 18 individuals ( for black-footed ferret)
If the annual survival rate in the wild was 0.4%.
a)
What is the probability that all 18 would have died in a single year?
To find that; we multiply the annual survival rate in the wild with the total population; which is:
(0.4%×18) = 0.072%
Then; we subtract it from a total of 100% in order to determine the probability that all 18 would have died in a single year.
= (100.00% - 0.072%)
= 99.93%
b)
What is the probability that all 18 would have died in a single year if canine distemper was present?
Given that;
Because of the presence of canine distemper disease, the annual mortality rate might have been as high as 0.89.
To determine the probability; we have:
1 - Annual mortality rate = annual survival rate
1 - 0.89 = 0.11 %
Therefore, 0.11% of 18 individuals = (0.0011 × 18)
= 0.0198%
Probability that all 18 would have died in a single year if canine distemper was present = 100 - probability of annual survival rate
= (100 - 0.0198)%
= 99.98%
<span>The correct answer is a. the overuse of fertilizer lead to reduced crop yields over time. This was unexpected because it is common for fertilizers to increase the yields and the quality of the product, but what happens over time is the opposite so it can be said that it's an unexpected consequence.</span>
Answer:
we can do it together.. we can do a zoom call.... im workingon that right now
Explanation:
lol im doin the same thing
What Paul and Nancy should do to ensure a fair comparison between all the hives is to d<span>ocument the number of bees as compared to the amount of honey per hive.
This is the only fair comparison, because they will know approximately how much each of the groups produced compared to the number of bees.
</span>
Water molecule, skin cell, E. Coli Bacteria, grain of salt, human
