To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Answer: A
Step-by-step explanation:
The nominal scale by definition only deals with non-numeric or non-quantitative variables or where numbers have no numerical value. The nominal scale uses tags or labels instead of number to classify or identify an object being measured.
<span>4(9n-9)
= 4*9n -4*9 (distributive property)
= 36n -36
The correct answer is c. </span>36n -36~
l = 2w + 4
l * w = 48
We can substitute l with its value:
2w + 4 * w = 48
2w^2 + 4w - 48 = 0
2(w^2 + 2w - 24) = 0
2(w+6)(w-4) = 0
w = {4, -6}
