Now, we know that he's charging $12 per session to each of his students, and he has 14 students currently, so his revenue is just 14 * 12 or 168 bucks.
now, let's take a peek as the session price goes up in jumps of 2, from 12, to 14, 16, 18 and so on, as each jumps happen, the students drop by 1, from 14, to 13, to 12 and so on.

notice, the revenue starts off at 168, goes up up, reaches 200 bucks and then starts to drop back down.
thus, that means the U-turn or vertex of that revenue function is at 4,200, namely h = 4, and k = 200

Answer:
1) 33 cm squared
2) 212.5 cm squared.
Step-by-step explanation:
1) Split the figure into a rectangle and a square. The rectangle is 8 (4 times 2) and the square is 25 (5 times 5). 25+8 =33.
2) Find the area of the shaded and unshaded. 14 times 25 equals 350. Then find the area of the unshaded triangle. 11 times 25 divided by 2 is 137.5. Now subtract. 350-137.5 = 212.5.
*please mark brainliest*
Answer:
The art is rectangular because 
(0.5) squared + (1.2) squared = (1.3) squared
Step-by-step explanation:
Given that the piece of art is rectangular in shape.
Length of piece of art = 0.5 meters
Width of piece of art = 1.2 meters
Kindly refer to the attached image in the answer area.
Two adjacent sides of a rectangle are given, the diagonal value can be found by using Pythagorean Theorem.
According to Pythagorean theorem:

Here, Hypotenuse will be the diagonal of the rectangle.
Base and Perpendicular will be the two adjacent sides.
Therefore,

Therefore, the answer is:
The art is rectangular because 
OR
(0.5) squared + (1.2) squared = (1.3) squared
18k - 4k = -10 - 4k
18k - 4k + 4k = -10
18k = -10
k= (18/10) = (9/5) = 1.8
Given:
μ = 197.5 cm, the population mean
σ = 7.98 cm, the population standard deviation
Part a.
For the random variable x = 207.50 cm, the z-score is
z = (x-μ)/σ = (207.5-197.5)/7.98 = 1.253
From standard tables, obtain
P(x < 207.5) = 0.895
Answer: 0.895
Part b.
n = 20, the sample size
σ/√n = 7.98/√(20) = 1.7844
The random variable is x = 196.0 cm
The z-score is
z = (x-μ)/(σ/√n) = (196 - 197.5)/1.7844 = -0.8406
From standard tables, obtain
P(x < 196) = 0.2003
Answer: 0.2003
Part c.
In part b, the sample size of 30 is less than the minimum recommended value of 30.
The reasons why the normal distribution can be used are
(i) the z-score takes the sample size into account because σ is replaced by
σ/√n.
(ii) according to the Central Limit Theorem, sample means are normally
distributed.