Cant figure this one out... if anyone can i would appreciate it

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

7 0

First of all, range means the value of y and domain means the value of x. then in order to solve for the question, you just need to put 9,12,15 into the equation as the value of y. then you will get the domain for those three numbers which are 3,4,5. so the answer would be the third option.

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Here goes another question: 4/5%9/10 and please if you can with procces

love history [14]

When you divide a fraction by another fraction, it is the same thing as multiplying that fraction by its reciprocal.

The reciprocal is the 'flipped' version of a fraction where the numerator becomes the denominator and the denominator becomes the numerator.

for example, the reciprocal of 9/10 is 10/9

Knowing this information 4/5÷9/10 is the same as 4/5×10/9

Now we can solve...

$\frac{4}{5} * \frac{10}{9} = \frac{40}{45} = \frac{8}{9}$

Answer= 8/9

7 0

4 years ago

Read 2 more answers

What is y+7/3=y/3 i really need help fast

Y_Kistochka [10]

Y should equal -7/2 or -3.5

3 0

3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$