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Flauer [41]
3 years ago
10

The M:N relationship between STUDENT and CLASS must be divided into two 1:M relationships through the use of the ENROLL entity;

the ENROLL entity is ____.
Computers and Technology
2 answers:
Leya [2.2K]3 years ago
4 0

Answer:

Weak entity.

Explanation:

A weak entity is that which might reside simply when it is possessed through any other thing or individual.

  • Such as, There would always be the room in a building.
  • In the other hand, a tire may be called a powerful force, although it may even reside without getting connected to a Vehicle.

Thus, from the above statement, the following answer is true

zubka84 [21]3 years ago
3 0

Answer:

The answer is "weak".

Explanation:

In the given statement some option is missing which can be described as follows:

A) weak  

B) strong  

C) optional

D) mandatory

The weak entity is an object, which could not be described specifically by its properties only, It should have a foreign key to create a primary key in comparison to its attributes, and wrong choices can be explained as follows:

  • In option B, It describes the relationship with the weak entities.
  • In option C, It describes the relationship, which is not necessary.
  • In option D, In every case, an entity could be affiliated with another entity, but this is not necessary.
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A personal phone directory contains room for first names and phone numbers for 30 people. Assign names and phone numbers for the
Fynjy0 [20]

Answer:

# include <iostream.h>

# include <stdio.h>

# include <string.h>

using namespace std;

class citizen

{      

    int i;

    public string name[30];

    public long int phonenumber[30];

    public void addindividual(string name1)

     {      

           If (i<=30)

            {     int flag=0;

                  for(int j=0; j<=i;j++)

                  {

                     if (strcmp(name[i], name1)

                      {

                          flag=1;

                      }

                     else

                     {  

                           flag=0;

                     }

                  }

                  If (flag)

                 {

                  if (i<30)

                  {

                  for(j=i+1;j<=30; j++)

                  {

                        cout<<"Enter the name:"; getchar(name[j]);

                        cout<<"Enter the phone number:"; cin>>phonenumber[j];

                         i++;

                   }

                  else  

                   {

                        cout<<"The person already exists";

                        exit();

                   }

              }

            else

             {

                 cout<<"array is full:";

                 exit();

             }

     }

}

Void main()

{

     string str;

    cout<<" Enter name:";

    getline(cin, str); ;

     citizen c1=new citizen();

     c1.addindividual(name1);

}

Explanation:

With a little more effort you can make the program allow the user to enter any number of details, but less than 30 overall. We have used here flag, and as a programmer we know why we use the Flag. It is used to check whether certain Boolean condition is fulfilled or not. Here, we are checking whether a given name is present in the array of names, and if it is not present, we add that to the list. And if the name is present, we print, it already exist.

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