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defon
2 years ago
9

What is the next number 3 4 6 9 13 18 24

Mathematics
2 answers:
AlexFokin [52]2 years ago
5 0
Basically, the number added increases by one each time.

3 + 1 = 4
4 + 2 = 6... etc

So, you have to add 7 to 24 to get the answer
24 + 7 = 31

The answer is 31
Ilya [14]2 years ago
3 0
31.
There's a pattern, +1, +2,+3,+4 ect. 
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Harlamova29_29 [7]

In math, Exponentiation refers to the operation of raising one quantity to the power of another. See the program running the exponentiation below.

<h3>What is the required code?</h3>

The code is given below:

number_of_days = 30

amount_after_30days = 0.01 * (2 ** number_of_days)

# print the amount

print(amount_after_30days)

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4 0
1 year ago
!!!25 Points HELP ME PLS ASAP
Lorico [155]

Answer:

$4.03

Step-by-step explanation:

because 15% of 3.50 is 0.525

take 0.525 and round it up (0.53)

3.50 + 0.53 = $4.03

7 0
2 years ago
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What is the volume of the cube below?
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Step-by-step explanation:

6 0
3 years ago
Calculate the value of the following determinants: | 1 -1 3 2 5 0 -3 1 2 | and | -1 -8 2 9 1 0 4 1 2 |
vitfil [10]

Answer:

1) The determinant = 65

2) The determinant = 152

Step-by-step explanation:

Let us show how to find the determinant of a matrix

You can find the determinant of this Matrix  \left[\begin{array}{ccc}a&b&c\\d&e&f\\g&m&n\end{array}\right]

by using this rule

Determinant = a(en - fm) - b(dn - fg) + c(dm - eg)

Let us use this rule with the given matrices

1)

 \left[\begin{array}{ccc}1&-1&3\\2&5&0\\-3&1&2\end{array}\right]

The determinand = 1[(5)(2) - (0)(1)] - (-1)[(2)(2) - (0)(-3)] + 3[(2)(1) - 5(-3)]

= 1[10 - 0] - (-1)[4 - 0] + 3[2 - (-15)]

= 1[10] + 1[4] + 3[2+15]

= 10 + 4 + 3[17]

= 10 + 4 + 51

= 65

The determinant = 65

Let us do the second one

2)

 \left[\begin{array}{ccc}-1&-8&2\\9&1&0\\4&1&2\end{array}\right]

The determinand = -1[(1)(2) - (0)(1)] - (-8)[(9)(2) - (0)(4)] + 2[(9)(1) - 1(4)]

= -1[2 - 0] - (-8)[18 - 0] + 2[9 - 4]

= -1[2] + 8[18] + 2[5]

= -2 + 144 + 10

= 152

The determinant = 152

6 0
3 years ago
First 10 to comment get thanks
Keith_Richards [23]
Hello! If you have any questions feel free to ask
8 0
3 years ago
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