I'm going to assume that the room is a rectangle.
The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.
You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.
The dimensions of your room are 25ft (length) by 24ft (width).
The only way to have two numbers that are the same and add up to be 15
is if they're both 7.5 , but those don't multiply to be 36. So I guess there's
no answer that satisfies all the conditions of this question.
Answer:
First of all cant give u the anssswer i am srry but i can give u a hint u need to find eqivelent fractions for the denominators then u can add them
Step-by-step explanation:
Hopefully this photo helps
Answer: x= 3/2 and y= 1/2
Step-by-step explanation:
Since both equations are equated to y, you just need to use substitution to create the equation below:
-x+2 = 3x-4
Solve the equation for x:
4x=6
x=6/4=3/2
Plug in x into any one of the given equations to find the value of y:
y=-x+2
y= - (3/2)+2
y= - (3/2)+4/2
y= 1/2
Hope this helps!