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Maru [420]
3 years ago
8

Find X round to the nearest tenth. Plz anwser

Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

\tan(35)  = x \div 24 \\ x = 24 \times  \tan(35)  \\ x = 16.8 \\  \\

to the nearest tenth it will be 17

You might be interested in
(a) A square has a perimeter of 20 m. What is the length of each side?
Goshia [24]

Answer:

A= 5

B= 3

Step-by-step explanation:

A= 5 +5+5+5= 20

B= 3 (length) x 3 (width)

5 0
3 years ago
Carlos started at sea level, climbed a
igomit [66]
19-14? I think first you need to find sea level.
8 0
3 years ago
Can somebody help me with this?
Natasha_Volkova [10]

Step-by-step explanation:

Hey there!

By looking through figure, l and m are parallel lines and a transversal line passes through the lines.

Now,

7x + 12° = 12x - 28°( alternate angles are equal)

12°+28° = 12x - 7x

40° = 5x

x =  \frac{40}{5}

Therefore, x = 8°

Now,

12x - 28° + 9y - 77 = 180° ( being linear pair)

12×8° - 28° + 9y -77° = 180°

96° - 28° + 9y - 77° = 180°

-9 + 9y = 180°

9y = 180° + 9°

y = 189°/9

Therefore, y = 21°

<u>There</u><u>fore</u><u>,</u><u> </u><u>X </u><u>=</u><u> </u><u>8</u><u>°</u><u> </u><u>and</u><u> </u><u>y</u><u>=</u><u> </u><u>2</u><u>1</u><u>°</u><u> </u><u>.</u>

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.
suter [353]

Answer:

The width of the photo is 4w^2+6w+4.

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

6w^2+8

The photo is covered by a frame border and the width of the border is

w^2-3w+2

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})

\text{Width of the photo}=6w^2+8-2(w^2-3w+2)

\text{Width of the photo}=6w^2+8-2w^2+6w-4

\text{Width of the photo}=4w^2+6w+4

Therefore the width of the photo is 4w^2+6w+4.

4 0
3 years ago
Five sevenths times seven thirds
lord [1]

5/7 x 7/3

Multiply the numerators together and the denominators:

(5 x 7) / (7 x 3)

35/21 reduces to 5/3 = 1 2/3

3 0
3 years ago
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