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qaws [65]
2 years ago
6

A car and a limo each drive along a straight road between two points. Using the points on a map that the city created, the car w

ill start at (5, 7) and will stop at (–2, –7), while the limo will start at (3, –5) and will stop at (–4, 9).
What are the coordinates of the intersection that the car and the limo both drive through?
Mathematics
2 answers:
garik1379 [7]2 years ago
8 0
The path of the car and the limo are straight lines. To determine the equation of the lines of the paths, the slopes must be determined. Let m1 = slope of car m2 = slope of limo so, m1 = (7 + 7)/(5 + 2) = 2 m2 = (-5 -9)/(3+4) = -2 therefore the equations are car: 2x – y = 2(5) –(7) 2x – y = 3 Limo: 2x + y = 2(3) – 5 2x + y = 1 Solving the intersection of the equations (using a calculator) x = 1 y = -1
hodyreva [135]2 years ago
7 0

Answer:

(1,-1)

Step-by-step explanation:

Given,

The starting point of the car is (5,7) and end point of the car is (-2,-7),

So, the equation that represents the position of car,

y-7=\frac{-7-7}{-2-5}(x-5)

y-7=\frac{-14}{-7}(x-5)

y-7=2(x-5)

y-7=2x-10

\implies 2x-y=3-----(1)

Similarly, the start point of the limo is (3,-5) and end point of the limo is (-4,9),

So, the equation that represents the position of limo,

y+5=\frac{9+5}{-4-3}(x-3)

y+5=\frac{14}{-7}(x-3)

y+5=-2(x-3)

y+5=-2x+6

2x+y=1----(2)

Adding equation (1) and (2),

4x = 4 ⇒ x = 1

From equation (1),

2(1) - y = 3 ⇒ -y = 3 - 2 ⇒ -y = 1 ⇒ y = -1

Hence, the intersection point of line (1) and (2) is (1,-1).

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Quadrilateral QRST is a square. If the measure of angle RQT is 3x - 6. Find the value of x.
trapecia [35]

Given that quadrilateral QRST is a square.

Each angle of a square is of 90 degrees.

Angle <RQT is also an angle of 90 degrees.

We also given angle RQT = 3x - 6.

So, we can setup an equation as 3x-6 =90.

Now, we need to solve the equation for x.

6 is being subtracted from left side.

We always apply reverse operation. Reverse operation of subtraction is addition.

So, adding 6 on both sides of the equation, we get

3x-6+6 =90+6.

3x = 96.

3 is being multipied with x, in order to remove that 3, we need to apply reverse operation of multiplication.

So, dividing both sides by 3.

\frac{3x}{3} = \frac{96}{3}

x=32 (final answer).

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Answer:

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Step-by-step explanation:

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