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icang [17]
3 years ago
13

Which of the following is not a polynomial

Mathematics
2 answers:
Aliun [14]3 years ago
7 0

Answer:

C. In a polynomial, you are not allowed to have a variable in a denominator.

dezoksy [38]3 years ago
3 0

Answer:

c

Step-by-step explanation:

because you can't have an exponent in the denominator

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John has 12 pounds of dog food and is going to separate it into 3/4 pound portions. How many portions of dog food will he have?
NNADVOKAT [17]

16 portions

explanation:

12 / 3/4

   = 12 * 4/3 

= 4*4 = 16

7 0
2 years ago
Eastridge High School’s Student Government Association is holding a raffle to raise money for a local food pantry. They have spe
Blababa [14]

"Interpret the rate of change and the y-intercept.

"

Rate of change is 5. Each ticket costs 5$.

Y-intercept is (0,-17). They spent $17 on supplies before they sold tickets.

(Sorry, you probably already know the answer)

5 0
3 years ago
The equation that corresponds to this diagram is 6 (x+ 1)=24.
Annette [7]

Answer:

x is 3

Step-by-step explanation:

6 (x + 1) = 24

6 (x) + 6(1) = 24

6x + 6 = 24

Subtract 6 on both sides

6x + 6 - 6 = 24 - 6

6x + 0 = 18

6x = 18

x = 18/6

x = 3

7 0
3 years ago
The velocity,v of a missile is related to time t, By the equation v=5t^2+3t+1.calculate the time at which the velocity is minimu
Cloud [144]

Answer:

  • time: t = -0.3
  • minimum: v = 0.55

Step-by-step explanation:

For quadratic ax^2 + bx + c, the extreme value is found at x=-b/(2a). For your quadratic, the minimum is found at ...

  t = -(3)/(2(5))

  t = -0.3 . . . . . time of minimum velocity

__

The value of velocity at that time is ...

  v = 5(-0.3)^2 +3(-0.3) +1 = 5(.09) -.9 +1

  v = 0.55 . . . . . value of minimum velocity

3 0
3 years ago
find the mean, median, and mode of the data set round to the nearest tenth 15, 1 , 4, 4, 8, 7, 15, 4, 5
Dmitriy789 [7]

15,\ 1,\ 4,\ 4,\ 8,\ 7,\ 15,\ 4,\ 15,\ 4,\ 5\to\underbrace{1,\ 4,\ 4,\ 4,\ 4,\ 5,\ 7,\ 8,\ 15,\ 15,\ 15}_{11}\\\\mean=\dfrac{1+4+4+4+4+5+7+8+15+15+15}{11}=\dfrac{82}{11}\approx7.5\\\\median:1,\ 4,\ 4,\ 4,\ 4,\ \boxed{5},\ 7,\ 8,\ 15,\ 15,\ 15\\\\mode:1,\ \underbrace{4,\ 4,\ 4,\ 4}_{4},\ 5,\ 7,\ 8,\ 15,\ 15,\ 15

<h3>Answer: mean = 7.5, median = 5, mode = 4</h3>
6 0
3 years ago
Read 2 more answers
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