Answer:
Both air balloon and water balloon data are best modeled by an exponential function.
Step-by-step explanation:
Air balloon
Time (seconds) Volume (cubic centimeters)
0 95
3 69
6 50
9 37
12 27
The relation Volume variation/time is constant for lines, In this case, this value change from point to point, as can be seen next.
(69 - 95)/3 = -8.67
(50 - 69)/3 = -6.33
(37 - 50)/3 = -4.33
(27 - 37)/3 = -3.33
Water balloon
Time (seconds) Volume (cubic centimeters)
0 30
3 15.8
6 7.8
9 4
12 2
(30 - 15.8)/-3 = -4.73
(15.8 - 7.8)/-3 = -2.67
(7.8 - 4)/-3 = -1.27
(4 - 2)/-3 = -0.67
In this case, the relation Volume variation/time also change from point to point.
Then, both air balloon and water balloon data are best modeled by an exponential function.
Answer:
- a. E = {1, 2, 3, 4, 5, 6, 7, 8}
- b. A ∩ B = {2, 3}
- c. A ∪ B = {1, 2, 3, 4, 5, 7, 8}
Step-by-step explanation:
Locate the designated space on the diagram and list all the numbers in it.
a. E = {1, 2, 3, 4, 5, 6, 7, 8} . . . . all numbers in the rectangle
__
b. A ∩ B = {2, 3} . . . . where the circles overlap
__
c. A ∪ B = {1, 2, 3, 4, 5, 7, 8} . . . . only 6 is outside the circles
Answer:
<h2>Solution: Since, the prime factors of 226 are 2, 113. Therefore, the product of prime factors = 2 × 113 = 226.</h2>
Step-by-step explanation:
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Answer: B
15cm and 9cm
Step-by-step explanation:
Answer: 11.2$
Step-by-step explanation:
