The subdural space is the space that exists between the meningeal layer of the dura and the arachnoid mater.
<h3>What is subdural space?</h3>
The subdural space which is also called subdural cavity, is a space within the dura mater that collects blood from the small veins of the brain so we can conclude that subdural space is the space that exists between the meningeal layer of the dura and the arachnoid mater.
Learn more about veins here: brainly.com/question/393019
Answer:
D. .................................
I think the answer is apes/monkeys are closely related with humans.
Answer:
Failure of chromosome to separate
Explanation:
The main essence of meiotic division is to form daughter cells with a reduced number of chromosomes that will maintain the correct chromosomal number in an organism. This is achieved when chromosomes separate during gamete formation (meiosis) to produce haploid (n) gametes.
However, a case may arise whereby chromosomes fail to separate during the anaphase stage of meiosis. This case is referred to as MEIOTIC NON-DISJUNCTION. As meiosis occurs in two stages i.e. meiosis I and II, so does meiotic nondisjunction. It can occur in meiosis I, where homologous chromosomes fail to separate or meiosis II, where sister chromatids fail to separate.
If it occurs in meiosis I, Two gametes will have a n-1 chromosome number i.e. one chromosome is missing while Two other gametes will have n+1 chromosome number i.e. one extra chromosome is added.
If it occurs in meiosis II, two normal haploid gametes (n) will be produced while the other two will have a n+1 and n-1 chromosome number respectively.
When these abnormal gametes (n+1, n-1) fuses with a normal gamete (n), the resulting organisms possess a chromosomal anomaly called ANEUPLOIDY i.e. a disorder in chromosomal number. The organisms will have 47 and 45 chromosomes depending on whether n+1 or n-1 gametes is involved respectively.
Answer:
Dominant
Explanation:
Let the allele for short tail trait be represented by "T" and allele for long tail trait be represented by "t"
When a short tailed mutant with genotype "tt" is mated with long tailed mouse, following offspring will be produced -
Tt * tt
Tt, Tt, tt, tt
so the ratio of short tailed and long tailed mouse is 1:1
Here it is given as 4:3 . Hence, there are chances that short tail trait is dominant
In the second generation , two short tailed mouse are crossed. The following offspring will be produced
Tt * Tt
TT, Tt, Tt, tt
The ration of short tailed and long tailed mouse is 3:1
Here it is given as 6:3 i.e 2:1 . Hence, short tail trait is dominant over long tail trait.
