Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
69 styles
Step-by-step explanation:
75%= 3/4
92/4= 23 (1/4)
23x3= 69
<span>Simplifying
7p + 2 = 5p + 8
Reorder the terms:
2 + 7p = 5p + 8
Reorder the terms:
2 + 7p = 8 + 5p
Solving
2 + 7p = 8 + 5p
Solving for variable 'p'.
Move all terms containing p to the left, all other terms to the right.
Add '-5p' to each side of the equation.
2 + 7p + -5p = 8 + 5p + -5p</span>
Answer:
all of those are shown inside of the triangle ...
Step-by-step explanation:
Answer:
c.126 red
Step-by-step explanation:
red+green+yellow=350
10% out of 350 are yellow
0.1 times 350=35
350-35=315
3/5 out of 315 are green
red is not green so
2/5 of what is left is red
2/5 of 315 is red
2/5 times 315=430/5=126
126 red
