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horrorfan [7]
4 years ago
12

During a recent beetle infestation, two-thirds of the ash trees in the area were destroyed. If 130 trees were destroyed, how man

y ash trees were originally in the area?
Mathematics
2 answers:
san4es73 [151]4 years ago
8 0

Answer:

195 Trees

Step-by-step explanation:

2/3 is just 2 of 3 parts

2 parts of the trees is 130,

so divide 130 by 2, and that's 65.

Since you know 65 + 65 is the same as 2 out of 3

Then just add 65 one more time to equal 195.

Since, 65*3 is the same as saying 1 * 3 parts

130 is equal to 2/3, so 195 is equal to 3/3.

SIZIF [17.4K]4 years ago
4 0
195.

set this up as a proportion with 2/3 = 130/x
130 x 3 = 390
390 / 2 = 195
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Take LCM ald then do in full process​please help me
Marina86 [1]

Answer:a) L.C.M OF 2,3,5 is 30

THEREFORE=60/30+15/30÷10/30-6/30

=60/30+15/30×30/10-6/30(DMAS)

=60/30+3/2-6/30

=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.

=105/30-6/30

=105-6/30

=99/30

=33/10

b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3

8 0
3 years ago
Which expression has a vaule of 2/3?
satela [25.4K]

Answer:

so the answer is 32/48

Step-by-step explanation:

(8+24)/(12*4)

32/48

2/3

i hope this helps

4 0
3 years ago
Chris wants to fence three sides of a rectangular exercise yard for his dog. The fourth side of the exercise yard will be a side
Semmy [17]

Answer:

  • parallel: 60 ft
  • perpendicular: 30 ft
  • area: 1800 ft^2

Step-by-step explanation:

Let x represent the length of fence parallel to the house. Then the length perpendicular is ...

  y = (120 -x)/2

The area of the yard is the product of these dimensions, so is ...

  A = xy = x(120-x)/2

This is the equation of a parabola that opens downward and has zeros at x=0 and x=120. The maximum (vertex) is on the line of symmetry, halfway between these zeros, at x=60.

The fence parallel to the house is 60 feet.

The fence perpendicular to the house is (120-60)/2 = 30 feet.

The area of the yard is (60 ft)(30 ft) = 1800 ft^2.

4 0
4 years ago
What does 8.4 10^5-7.7 10^4 equal?
Alex

Answer:

\huge\boxed{763,000=7.63\cdot10^5}

Step-by-step explanation:

\bold{METHOD\ 1:}\\\\8.4\cdot10^5-7.7\cdot10^4=8.4\cdot100,000-7.7\cdot10,000\\\\=840,000-77,000=763,000\\\\\bold{METHOD\ 2:}\\\\8.4\cdot10^5-7.7\cdot10^4=8.4\cdot10^{1+4}-7.7\cdot10^4\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=8.4\cdot10^1\cdot10^4-7.7\cdot10^4=84\cdot10^4-7.7\cdot10^4\\\\\text{use the distributive property}:\qquad a(b+c)=ab+ac\\\\=(84-7.7)\cdot10^4=76.3\cdot10^4=7\underbrace{.63}_{\leftarrow1}\cdot10^{4+1}=7.63\cdot10^5

5 0
3 years ago
How do you do this question?
vaieri [72.5K]

Answer:

(-∞, -2), (-2, -0.618), and (1.618, 3)

Step-by-step explanation:

The red plus (+) signs indicate the regions in which the function is concave up, and the red negative (-) signs indicate the regions in which the function is concave down.

Note that the sign of the concavity changes at an inflection point.

Let's examine the intervals given.

(-∞, -2): Yes, concave up.

(-∞, -1.17): No. Concave up in (-∞, -2) but concave down in (-2, -1.17).

(-2, 0): No. Concave down in (-2, -1.17) but increasing in (-1.17, 0.0).

(-1.17, 0.689): Yes. Concave up.

(-0.618, 1.618): No. Concave up in (-0.618, 0.689) but concave down in (0.689, 1.618).

(0, 3): No. Concave up in (0, 0.689), concave down in (0.689, 2.481), and concave up in (2.481, 3).

(2.481, ∞): Yes. Concave up.

The three intervals that are concave up are (-∞, -2), (-1.17, -0.689), and (2.481, ∞).

4 0
3 years ago
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