Answer:
f'(x) = 5 x<4
= 2x 4<x<6
= 4 x>6
Domain is all real numbers except 4 and 6
Step-by-step explanation:
We need to find the derivative of the piecewise function
f'(x) = 5 x<4
= 2x 4≤x≤6
= 4 x>6
Is the function continuous at 4
f(4-) = 5(4) - 6 = 20-6 = 14
f(4+) = 4^2 -2 = 16-2 = 14
this is continuous, so there is no problem with the continuity here
Is the function continuous at
f(6-) = 6^2 -2 = 36-2 = 34
f(6+) = 4(6)+10 = 24+10 = 34
this is continuous, so there is no problem with the continuity here
Now we need to check the derivatives
f'(4-) = 5
f'(4+) = 8
This is not continuous, so we get a piecewise definition for the derivative excluding 4
f'(6-) =12
f'(6+) =4
This is not continuous, so we get a piecewise definition for the derivative excluding 6
Since the bucket has already a mass of 2,000 kg, therefore
the maximum mass of gravel would only be:
15,000 kg – 2,000 kg = 13,000 kg gravel
Solving for volume:
volume = 13,000 kg / (1,500 kg / 1 m^3)
volume = 8.67 m^3
<span>Therefore about 8.67 cubic meter of gravel can be safely
loaded by the crane.</span>
Answer:
0.75 x 7 = 5.25
9-5.25=3.75
3.75/0.38=
9.86
round down because the rope has to be full
9 is your answer
Step-by-step explanation:
Answers:
- Original = 1 ----> Enlarged = 6
- Original = 7 ----> Enlarged = 42
- Original = 2.5 ----> Enlarged = 15
- Original = 6 ----> Enlarged = 30
It looks like you have the correct order. To get those answers above, we simply multiply the original length by the scale factor 6.
Example: 7*6 = 42
A=2πrh+2πr2=2·π·6·25+2·π·6^2 so the answer is D
