Find the distance between (2, 3) and (–4, 4). If necessary, round to the nearest tenth.
2 answers:
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Answer:
A'(2, 6 )
Step-by-step explanation:
Assuming the dilatation is centred at the origin, then multiply each of the coordinates by
A(3, 9 ) → A'( (3),
(9) ) → A'(2, 6 )
Please refer to the diagrams to understand these answers:
CUBE (1):
Paint on cube (1) contains 3.125% of the paint.
CUBE (2):
Paint on cube (2) contains 2.083% of the paint.
CUBE (3):
Paint on cube (3) contains 1.042% of the paint.
CUBE (4):
Contains 0% of the paint.
-----------------
There would be four different types of cubes which would contain different amounts of paint.
Some cubes in fact would have no paint (cube (4)). Now we can check if our results are correct by counting how many cube (1)'s, cube (2)'s, cube (3)'s and cube (4)'s there are...
Cube (1) x 8 + Cube (2) x 24 + cube (3) x 24 + cube (4) x 8
= 3.125% x 8 + 2.083% x 24 + 1.042% x 24 + 0% x 8
= 1
= 100%
CUBE (1):
Paint on cube (1) contains 3.125% of the paint.
CUBE (2):
Paint on cube (2) contains 2.083% of the paint.
CUBE (3):
Paint on cube (3) contains 1.042% of the paint.
CUBE (4):
Contains 0% of the paint.
-----------------
There would be four different types of cubes which would contain different amounts of paint.
Some cubes in fact would have no paint (cube (4)). Now we can check if our results are correct by counting how many cube (1)'s, cube (2)'s, cube (3)'s and cube (4)'s there are...
Cube (1) x 8 + Cube (2) x 24 + cube (3) x 24 + cube (4) x 8
= 3.125% x 8 + 2.083% x 24 + 1.042% x 24 + 0% x 8
= 1
= 100%