You have to first mess around with the first shape, ABCD, and split that into a rectangle and a right triangle. once you do that, it's pretty painstaking, but simple.
if you look at it you can tell that EFGH is just half the size, but the same ratios and everything.
So, you would just take every perimeter measurement from ABCD, and divide it by two and then sum them together.
2.5 + 1.5 + 4.0 + 2.0 = 10
Answer:
Step-by-step explanation:
Given that,
Renee has 1/4 yard of floral fabric.
She cuts it into 5 equal pieces.
We need to find the length of each new piece of fabric. It is equal to the total length divided by the total number of pieces. So,
So, each new piece pf fabric is .
Answer: the distance from one corner of the field to the other corner is 136 m
Step-by-step explanation:
The distance from one corner to the other corner is the diagonal and it
divides the field into two equal right angle triangles. The diagonal represents the hypotenuse of each right angle triangle. The length and width of the rectangle represents the adjacent and opposite sides of the right angle triangle. To determine the length of the diagonal, d, we would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side²
Therefore
d² = 110² + 80²
d² = 12100 + 6400 = 18500
d = √18500
d = 136 meters
<span>100. Since 10 shirts x 2 slacks means 20 combos with one tie and 100 with 5 ties</span>
Answer:
t = 2
Step-by-step explanation:
Notice that this expression for the projectile's path is that of a quadratic function with negative leading term. The graph of it therefore consists of a parabola with the branches pointing down (due to he negative leading coefficient). Therefore, the maximum of such parabola will reside at its vertex.
Recall that the formula for the position of the vertex in a general parabolic function of the form: 
, is given by the expression: 
In our case, the variable "x" is in fact "t", the leading coefficient (
) is -5, and the coefficient for the linear term (
) is 20.
Therefore, the maximum of the path will be when 
