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jekas [21]
3 years ago
7

The ratio 2.5m to 60cm can be written in the form 1:n find the value of n. someone please help asap

Mathematics
2 answers:
Stells [14]3 years ago
8 0

Answer:

1 : 6/25

Step-by-step explanation:

Convert 2.5 meters to cm

We know 100 cm = 1m

2.5 m * 100cm / 1m = 250 cm

250 cm : 60 cm

Divide by 250

250/250 = 60/250

1 : 6/25

or as a decimal

1 :  .24

Svetach [21]3 years ago
5 0

Answer:

24

Step-by-step explanation:

2.5 divided by 2.5 equals 1. So 60 divided by 2.5 equals 24.

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Answer:

234.85

Step-by-step explanation:

4 days earning = $85.40

so, 1 day earning will be = $85.40/4 = $21.35

Now, 11 days earning would be: $21.35 * 11 = $234.85

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3 years ago
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A taxi charges 2.50 plus .50 fee for each mile. If the ride costs 7.50 how many miles did he travel
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Answer:<em> 10 miles</em>

Step-by-step explanation:

<em>Mile 1: 3.00</em>

<em>Mile 2: 3.50</em>

<em>Mile 3: 4.00</em>

<em>Mile 4: 4.50</em>

<em>Mile 5: 5.00</em>

<em>Mile 6: 5.50</em>

<em>Mile 7: 6.00</em>

<em>Mile 8: 6.50</em>

<em>Mile 9: 7.00</em>

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7 0
2 years ago
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oksano4ka [1.4K]

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3 0
3 years ago
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Answer:

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8 0
3 years ago
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A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
qaws [65]

The projectile's horizontal and vertical positions at time t are given by

x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t

y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2

where g=9.8\dfrac{\rm m}{\mathrm s^2}. Solve y=0 for the time t it takes for the projectile to reach the ground:

30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s

In this time, the projectile will have traveled horizontally a distance of

x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m

The projectile's horizontal and vertical velocities are given by

v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ

v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about \sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}.

7 0
3 years ago
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