Answer:
v = 1.36 cm / y
Explanation:
For this exercise we must assume that the displacement of the plates is constant over time, so we will use the kinematic relationships for the uniform movement
v = d / t
We reduce the quantities to the SI system
d = 320 km (1000 m / 1km) (100 cm / 1 m)
d = 3.2 107 cm
let's calculate
v = 32.107 / 23.5 106
v = 1.36 cm / y
Higher frequency,higher energy,shorter wavelength
Initial velocity, u = 0
Final velocity, v = 60 m/s (at take off)
Duration of the acceleration, t = 4 s
Calculate average acceleration.
a = (v - u)/t
= (60 m/s)/(4 s)
= 15 m/s²
Calculate the distance traveled during acceleration.
s = ut + (1/2)*a*t²
= 0.5*(15 m/s²)*(4 s)²
= 120 m
Answer: 120 m
Answer:
B
Explanation:
Just answerd that question!!!
<u><em>Hope it helped!!!</em></u>
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Answer:
a. V3 = 19.36m/s
b. β3 = -18.8°
Explanation:
Our given data is:
mt = 6.4kg; Vo = [10.2*cos(35°), 10.2*sin(35°)] m/s
m1 = 1.4kg; V1 = [-3.7, 0] m/s
m2 = 1.8kg; V2 = [0, 11.1] m/s
By inspection:
m3 = 3.2kg V3 = [ V3x, V3y]
At the point where the ball explodes, there's only x-component of the velocity, so:
Pix = Pfx and Piy = Pfy
On x-axis:
mt * Vo*cos(35°) = m1 * V1x + m3 * V3x
Solving for V3x:
V3x = 18.33 m/s
On y-axis:
0 = m2 * V2y + m3 * V3y
Solving for V3y:
V3y = -6.24 m/s
Therefore, the magnitude is:
The angle is: