Just like mass, energy, linear momentum, and electric charge, angular momentum is also conserved.
The wheel has angular momentum. I don't remember whether it's
up or down (right-hand or left-hand rule), but it's consistent with
counterclockwise rotation as viewed from above.
When you grab the wheel and stop it from spinning (relative to you),
that angular momentum has to go somewhere.
As I see it, the angular momentum transfers through you as a temporary
axis of rotation, and eventually to the merry-go-round. Finally, all the mass
of (merry-go-round) + (you) + (wheel) is rotating around the big common
axis, counterclockwise as viewed from above, and with the magnitude
that was originally all concentrated in the wheel.
The formula for acceleration is the velocity times the inverse of time so it would be 21 times 1/13. So roughly 0.0769... is the acceleration(m/s^2).
Answer:
The correct answer to the following question will be "Period".
Explanation:
The Period seems to be the time deemed necessary for such a perfect cycle of vibration to transfer a particular moment. Because as the amplitude of the wave raises, the wavelength falls.
It is denoted by "T" and its formula will be:
⇒ 
Where, T = Period
F = Frequency
The other given choices are not related to the given circumstances. So that the above would be the right answer.
Answer:
A, 0.050 Hz
Explanation:
1) Frequency = speed divided by wavelength
time is 2* 60 = 120 seconds
distance = 6 wave lengths
speed = distance divided by time
speed = 6 wave lengths divided by 120
Hope this helps!
