The experiment that led scientists to change from the previous model to the one shown is that; the colors of light emitted from heated atoms had very specific energies.
The model of the atom showed in the image is the Bohr model of the atom. This model was the successor of the Rutherford model of the atom.
This model proposed that electrons were found in specific energy levels that has a definite value of energy.
This was arrived at after he discovered by experiments that the colors of light emitted from heated atoms had very specific energies.
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Answer:
d = 5 inch
Explanation:
First to all we need to get the expression to calculate the horsepower.
The expression to use is the following:
hp = k * v * d³ (1)
Where:
hp: horsepower
v: speed (in rpm)
d: diameter
k: constant of horsepower.
The value of k, because is a constant, will be the same when the shaft is transmiting 375 hp at 50 rpm. So, with the first data, we can calculate the value of k, and then, the value of the diameter
Solving for k in (1) we have:
k = hp / v * d³
replacing the data:
k = 36 / 75 * 2³
k = 0.06
With this value, we can solve for d and we have:
d = ∛hp / k * v
d = ∛375 / 50 * 0.06
d = 5 inch
Answer:
they are the same
Explanation:
change in speed is 10km/h for both, and the time is the same for both. they have the same acceleration.
Answer:
4.81x10³ Ω*m
Explanation:
The resistivity (ρ) of the skin can be calculated using the following equation:
<u>Where:</u>
<em>R: is the electrical resistance of the skin = 500x10³ Ω</em>
<em>A: is the cross-sectional area of the skin</em>
<em>l: is the length of the skin= 1.6 m</em>
Since we can model the body between the hands as a cylinder, the cross-sectional area is:
Now, we can fin the resistivity (ρ) of the skin:
Therefore, the resistivity of the skin is 4.81x10³ Ω*m
I hope it helps you!
Answer:
1.696 nm
Explanation:
For a diffraction grating, dsinθ = mλ where d = number of lines per metre of grating = 5510 lines per cm = 551000 lines per metre and λ = wavelength of light = 467 nm = 467 × 10⁻⁹ m. For a principal maximum, m = 1. So,
dsinθ = mλ = (1)λ = λ
dsinθ = λ
sinθ = λ/d.
Also tanθ = w/D where w = distance of center of screen to principal maximum and D = distance of grating to screen = 1.03 m
From trig ratios 1 + cot²θ = cosec²θ
1 + (1/tan²θ) = 1/(sin²θ)
substituting the values of sinθ and tanθ we have
1 + (D/w)² = (d/λ)²
(D/w)² = (d/λ)² - 1
(w/D)² = 1/[(d/λ)² - 1]
(w/D) = 1/√[(d/λ)² - 1]
w = D/√[(d/λ)² - 1] = 1.03 m/√[(551000/467 × 10⁻⁹ )² - 1] = 1.03 m/√[(1179.87 × 10⁹ )² - 1] = 1.03 m/1179.87 × 10⁹ = 0.000848 × 10⁻⁹ = 0.848 × 10⁻¹² m = 0.848 nm.
w is also the distance from the center to the other principal maximum on the other side.
So for both principal maxima to be on the screen, its minimum width must be 2w = 2 × 0.848 nm = 1.696 nm
So, the minimum width of the screen must be 1.696 nm