A 10 kg object has 500 joules of kinetic energy because of its speed. How fast is the object traveling?

Suppose a new star cluster is born with one o star, 10 a stars, 100 g stars, and 1000 m stars. which stellar type dominates the

uranmaximum [27]

Stars are classified by their spectra (the elements that they absorb) and their temperature. There are seven main types of stars. In order of decreasing temperature, O, B, A, F, G, K, and M. Type O stars are the stars with the highest temperature and biggest luminosity. So, if there is a new born star cluster : 1. with one O star,
2. with 10 A stars,
3. with 10 G stars,
4. with 1000 M stars

the stellar type O will dominate the light output from the cluster.

6 0

3 years ago

All neutron stars are things that produce intense gravity. All neutron stars are extremely dense objects. Therefore, all extreme

nika2105 [10]

Answer:

Major term is 'things that provide intense gravity'

Minor term is 'extremely dense objects'

Middle term is 'neutron stars'

Explanation:

Major term is given by the predicate part of the conclusion
Minor term is given by the subject part of sentence in conclusion
Middle term is given by the subject part and not the conclusion

6 0

4 years ago

When a rigid body rotates about a fixed axis, all the points in the body have the same A. centripetal acceleration B. tangential

Leto [7]

Answer:

The angular acceleration is same at all the points in the body.

Option (D) is correct.

Explanation:

Given:

When a rigid body rotates about a fixed axis, all the points in the body have the same,

For finding which quantity is same we use pure rotational concept,

$v = \omega r$

Where $\omega =$ angular frequency, $r =$ radius of rigid body

When a rigid body rotates about a fixed axis angular velocity of all the points in the body are same.

But the tangential speed, tangential acceleration, linear displacement, and centripetal acceleration depend on the position of the points and hence they are not the same.

Therefore, the angular acceleration is same at all the points in the body.

8 0

3 years ago

In gas chromatography, what are the advantages of (a) temperature programming? (check all that apply.)

TiliK225 [7]

The following statements apply:
1. Resolution of low boiling solutes is maintained.
2. Retention times of high boiling solutes are decreased.
Temperature programming refers to the process of increasing the temperature of gas chromatography column as a function of time. Temperature programming is usually applied to samples which contain a mixture of components whose boiling points are within narrow ranges

3 0

3 years ago

How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?

tatyana61 [14]

Missing part in the text of the problem:
"Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
$Q=m C_s \Delta T$
where
m=1.8 g is the mass of the water
$C_s = 4.18 J/(g K)$ is the specific heat capacity of the water
$\Delta T=2.5 K$ is the increase in temperature.

Substituting the data, we find
$Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E$

We know that each photon carries an energy of
$E_1 = hf$
where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:
$\lambda = \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{3 \cdot 10^{-6} m}=1 \cdot 10^{14}Hz$

So, the energy of a single photon of this frequency is
$E_1 = hf =(6.6 \cdot 10^{-34} J)(1 \cdot 10^{14} Hz)=6.6 \cdot 10^{-20} J$

and the number of photons needed is the total energy needed divided by the energy of a single photon:
$N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons$

4 0

3 years ago