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Answer:
y = -(1/12)(x -6)² -2
Step-by-step explanation:
The vertex of the parabola is halfway between the focus and the directrix, so has y-coordinate (-5+1)/2 = -2. The difference in the y-coordinates between the focus and the vertex is ...
p = -5 -(-2) = -3
An equation of the parabola with vertex (h, k) and focus-vertex distance p can be written:
y = 1/(4p)(x -h)² +k
For (h, k) = (6, -2) and p = -3, the equation is ...
y = (-1/12)(x -6)² -2
