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yan [13]
2 years ago
10

The sum of 2 fractions is 5/6. Their difference is 1/2. Their least common denominator is 6. The denominator of one is twice the

size of the other. The sum of their numerators is 3. Find both fractions.
Mathematics
1 answer:
valentinak56 [21]2 years ago
7 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose the first fraction is : \frac{a}{b}

Suppose the second fraction is : \frac{c}{d}

The sum of both fraction is given as : \frac{5}{6}

\frac{a}{b}+\frac{c}{d}=\frac{5}{6}    .......................equation (1)

The difference of both fraction is given as : \frac{1}{2}

\frac{a}{b}-\frac{c}{d}=\frac{1}{2}   .........................equation (2)

Adding equation (1) and equation (2)

\frac{c}{d} \ will  \ be \ cancelled

\frac{2a}{b}=\frac{5}{6}+\frac{1}{2}

making common denominator

\frac{2a}{b}=\frac{5}{6}+ \frac{3}{6}

\frac{2a}{b}=\frac{8}{6}

Hence,

\frac{a}{b}=\frac{2}{3}

Plugging the value of \frac{a}{b} in equation (1)

\frac{2}{3}+\frac{c}{d}=\frac{5}{6}

Subtracting \frac{2}{3} in both sides

\frac{c}{d}=\frac{5}{6}-\frac{2}{3}

\frac{c}{d}=\frac{1}{6}

Hence both fractions are \frac{2}{3} \ and \  \frac{1}{6}     ...................Answer

Hope it will help :)

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vichka [17]

Answer:

1.  Formula is A2 : A9 = COUNT( A2: A9 ) = 8

2. Formula is SUM( A2: A9 ) = 36

3. Formula is B2 : B9 = COUNT( B2: B9) = 8

4. Formula is  MAX( C2: C9) = 5

5. Formula is MIN( C4: C8) = 3

6. Formula is SUM( C5 - C6) = 0

7. Formula is AVERAGE( C2: C9) = 4

Step-by-step explanation: Have a nice day! ✌️

7 0
2 years ago
The current temperature is 48°F. It is expected to drop 1.5°F each hour.
Lostsunrise [7]

Answer:

B

Step-by-step explanation:

5 0
1 year ago
Estimate the solution to the system of equations. asap, please!! I will mark for brain list
Darya [45]

Answer:

(1 \frac{1}{3}, 2 \frac{1}{3} )

Step-by-step explanation:

Given the 2 equations

7x - y = 7 → (1)

x + 2y = 6 → (2)

Multiplying (1) by 2 and adding to (2) will eliminate the y- term

14x - 2y = 14 → (3)

Add (2) and (3) term by term to eliminate y

15x = 20 ( divide both sides by 15 )

x = \frac{20}{15} = \frac{4}{3} = 1 \frac{1}{3}

Substitute this value of x into either of the 2 equations and solve for y

Substituting in (2)

\frac{4}{3} + 2y = 6

2y = 6 - \frac{4}{3} = \frac{14}{3} ( divide both sides by 2 )

y = \frac{7}{3} = 2 \frac{1}{3}

7 0
3 years ago
Factor. 21x^2 -32x+12
baherus [9]
Through trial and error:
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Usually it works best to test out a number of possibilities :)
3 0
3 years ago
What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE
maks197457 [2]

Given:

The equation of a line is:

2y+3x=10

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

2y+3x=10

For x=0,

2y+3(0)=10

2y+0=10

y=\dfrac{10}{2}

y=5

For x=2,

2y+3(2)=10

2y+6=10

2y=10-6

2y=4

Divide both sides by 2.

y=\dfrac{4}{2}

y=2

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

(x,y)\to (3x,3y)

Using this rule, we get

A(0,5)\to A'(3(0),3(5))

A(0,5)\to A'(0,15)

Similarly,

B(2,2)\to B'(3(2),3(2))

B(2,2)\to B'(6,6)

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-15=\dfrac{6-15}{6-0}(x-0)

y-15=\dfrac{-9}{6}(x)

y-15=\dfrac{-3}{2}x

Multiply both sides by 2.

2(y-15)=-3x

2y-30=-3x

2y+3x=30

Therefore, the equation of the line after the dilation is 2y+3x=30.

3 0
2 years ago
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