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2 years ago

What are the outputs of the function below?

Mathematics

1 answer:

Goryan [66]2 years ago

5 0

The outputs of the function are 6, 2, 3, 4 and input of the function are -1, 0, 7, and 10.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

x g(x)

–1 6

0 2

7 -3

10 4

The table shows the input and output of the function g(x)

g(-1) = 6

g(0) = 2

g(7) = -3

g(10) = 4

In the function represented by the table given, the set of corresponding y-values are: 6, 2, 3, 4.

Thus, the outputs of the function are 6, 2, 3, 4 and input of the function are -1, 0, 7, and 10.

Learn more about the function here:

brainly.com/question/5245372

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Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

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a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%$

$P(20 \leq x \leq 30) = 55.88\%$

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36$

c) P(mean score of sample is between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%$