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spayn [35]
3 years ago
9

An object has 15 grams of atoms and displaces 2.5 mL of water when dropped into a cylinder. What is the objects density?

Chemistry
1 answer:
Softa [21]3 years ago
7 0

Answer:

<h3>The answer is 6 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 15 g

volume = 2.5 mL

We have

density =  \frac{15}{2.5}  \\

We have the final answer as

<h3>6 g/mL</h3>

Hope this helps you

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A 25.0 mL aliquot of 0.0430 0.0430 M EDTA EDTA was added to a 56.0 56.0 mL solution containing an unknown concentration of V 3 +
Nady [450]

Answer:

Check the explanation

Explanation:

As we know the reaction of  EDTA and Ga^3+ and EDTA and V^3+

Let us say that the ratio is 1:1

Therefore, the number of moles of Ga^3+ = molarity * volume

                                    = 0.0400M * 0.011L

                                    = 0.00044 moles

Therefore excess EDTA moles = 0.00044 moles

Given , initial moles of EDTA  = 0.0430 M * 0.025 L

                                        = 0.001075

Therefore reacting moles of EDTA with V^3+ = 0.001075 - 0.00044 = 0.000675 moles

Let us say that the ratio between V^3+ and EDTA is 1:1

Therefore moles of V^3+ = 0.000675 moles

Molarity = moles / volume

                                    = 0.000675 moles / 0.057 L

                                    = 0.011 M (answer).

4 0
3 years ago
Identify the unit cell that has a = B = y = 90°.
elixir [45]

Monoclinic I think. I'm not sure

8 0
3 years ago
1.
Licemer1 [7]

Answer:

B. Yes, because the mass of all the products of burning is equal to the mass

of the reactants (wood and oxygen gas).

Explanation:

good luck

3 0
3 years ago
What is required before using a respirator? A.nothing B.proper training C.survey of the work area D.users guide
OLga [1]
I would say B but it might be D
8 0
3 years ago
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30,000 J of heat are added to 23.0 kg of steel to reach a final temperature of 140
kolbaska11 [484]

The initial temperature is 137.34 °C.

<u>Explanation:</u>

As the specific heat formula says that the heat energy required is directly proportional to the mass and change in temperature of the system.

Q = mcΔT

So, here the mass m is given as 23 kg, the specific heat of steel is given as c = 490 J/kg°C and the initial temperature is required to find with the final temperature being 140 °C. Also the heat energy required is 30,000 J.

ΔT =\frac{Q}{mc}

ΔT =\frac{30000}{23 \times 490} = \frac{30000}{11270} =2.66

Since the difference in temperature is 2.66, then the initial temperature will be

Final temperature - Initial temperature = Change in temperature

140-Initial temperature = 2.66

Initial temperature = 140-2.66 = 137.34 °C

Thus, the initial temperature is 137.34 °C.

7 0
3 years ago
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