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JulsSmile [24]
3 years ago
14

What is the molarity of a solution where 2.2 mol of KCl is dissolved to make 5.7 L of solution?

Chemistry
1 answer:
dangina [55]3 years ago
5 0

Answer:

0.385 mol/liter

Explanation:

number of moles÷volume in liters

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Boyle's Law expresses the pressure-volume
Colt1911 [192]

Answer:

\large \boxed{\text{175. atm}}

Explanation:

Data:

p₁ = 1.00 atm; V₁ = 350.      L

p₂ = ?;             V₂ =     2.00 L

Calculation:

\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{1.00 atm} \times \text{350. L} & = & p_{2} \times\text{2.00 L}\\\text{350. atm} & = & 2.00p_{2}\\p_{2} & = & \dfrac{\text{350. atm}}{2.00}\\\\& = &\textbf{175. atm}\\\end{array}\\\text{It would take a pressure of $\large \boxed{\textbf{175. atm}}$ to compress the gas.}

8 0
3 years ago
On a small farm, the weights of eggs that young hens lay are normally distributed with a mean weight of 51.3 grams and a standar
Lelechka [254]

Answer:

83.85% of the population is between 46.5g and 65.7g

Explanation:

the 68-95-99.7 rule states that the probability that a random variable (X=Weights of the eggs) is found inside 1 standard deviation , 2 standard deviations and 3 standard deviations from the mean is 68% , 95% , 99.7% respectively

then calling Z to

Z= (X-μ)/σ

where μ= mean , σ = standard deviation , then

for X₁=46.5g

Z₁= (X₁-μ)/σ = (46.5g - 51.3g)/4.8 g= -1

1 standard deviation from both sides (±1) = 68%

then since the normal distribution is symmetrical

1 standard deviation from one side (±1) = 68%/2 = 34%

for X₂=46.5g

Z₂= (X₂-μ)/σ = (65.7 g - 51.3g)/4.8 g= +3

3 standard deviation from both sides (±1) = 99.7%

then since the normal distribution is symmetrical

3 standard deviation from one side (±1) = 99.7%/2 = 49.85%

then

between -1 standard deviation from the mean and +3 standard deviations from the mean there is= 34% +  49.85% = 83.85% of the population (since the regions do not overlap each other)

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