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Lyrx [107]
3 years ago
5

Which element is placed in the same period as ruthenium but has a higher atomic number than it?

Chemistry
1 answer:
emmasim [6.3K]3 years ago
8 0

Answer:

The part that is put in the same time as ruthenium, but has a greater number of atoms than silver.

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It detects ionizing radiation<span> such as alpha particles, beta particles and gamma </span>rays<span>using the ionization effect produced in a </span>Geiger<span>–Müller tube; which gives its name to the instrument.</span>
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3 years ago
The boiling point of water is a _____ property and is equal to _____.
lisov135 [29]

Answer:

C. physical; 100°C

3 0
3 years ago
Read 2 more answers
Use the bond energies to answer the question.
Schach [20]

Answer:

D

Explanation:

Hello!

This is a topic I just learned this year so I might not help the best as of explaining. But I will try my best.

To solve this problem, we must first figure the balanced equation.

H₂+O₂=H₂O₂

Now, we have to find the bond energy of the reactants and products. This is how.

Let's find the reactant first.

For the compound H₂, the Lewis dot structure says that it only consists of one singular bond. So the bond energy of H₂ would be 432.

For the compound O₂, the Lewis dot structure that is the best out of the resonance structures form a double bond. Let's use the bond energy 495 for this since there are double bonds and we need the corresponding double bond energy to make the bond energy accurate.

Let's add this amount together. 927

Now, we have to find the bond energy of the products.

H₂O₂ sounds complicated but it's fairly easy. When you write the Lewis dot structure for this specific compound, you will get something along the lines of this:

H-O-O-H (disregarding lone pairs)

In this compound, there are two bonds of H-O and one bond that is a O-O. This might take you a long time to see this, but just think of what atom is touching the atom next door. This might help distinguish the bonds there are between the compound.

Let's take the bond energy of H-O (467) and multiply this by two since we have two. Add that number to the bond energy of O-O (146). We should have the numbers 1080.

Since the problem is asking for the difference in total energy between the reactants and products, let's subtract the total bond energy of the products-reactants.

1080-927=153

Therefore, your final answer of the total bond energy is 153.

4 0
2 years ago
Which one of the following pairs of separation techniques will BOTH separate salt from a mixture of salt and water?
Natali5045456 [20]

Answer:

What are the options and i dont know what the options are but if one of them is distilation im 99.9% sure that is the answer.

Explanation:

Be sure to friend me and mark me as braniliest if im correct!

6 0
3 years ago
In going across a row of the periodic table, protons and electrons are added and ionization energy generally increases. In going
RoseWind [281]

Answer:

Explanation:

Ionization energy:

It is the minimum amount of energy required to remove the electron from isolated gaseous atom to make the ion.

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell.

When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.  Where as,

When we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

4 0
3 years ago
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