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nekit [7.7K]
3 years ago
8

What is the wavelength of radiation that has a frequency of 7.2×10^11 s−1 ?

Chemistry
1 answer:
Airida [17]3 years ago
6 0

Explanation:

It is known that relation between wavelength and frequency is as follows.

                  \lambda = \frac{c}{\nu}

where,        \lambda = wavelength

                       c = speed of light = 3 \times 10^{8} m/s

                  [/tex]\nu[/tex] = frequency

It is given that frequency is 7.2 \times 10^{11} s^{-1}. Hence, putting this value into the above formula and calculate the wavelength as follows.

                    \lambda = \frac{c}{\nu}

                    \lambda = \frac{3 \times 10^{8} m/s}{7.2 \times 10^{11} s^{-1}}

                             = 0.416 \times 10^{-3} m

or,                         = 4.16 \times 10^{-4} m

Thus, we can conclude that wavelength of given radiation is 4.16 \times 10^{-4} m.

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Consider the balanced equation below.
Karo-lina-s [1.5K]

The correct option is (a) H₂S : SO₂ = 2 : 2 and O₂ : H₂O = 3 : 2

<h3>What is molar Ratio ?</h3>

Molar ratio also known as stoichiometry is the ratio in which the reactants and products are either formed or reacted in the given equation

the balanced equation is as follows ;

2H₂S + 3O₂ --> 2SO₂ + 2H₂O

molar ratio can be determined by the coefficients of the compounds in the balanced reaction.

coefficient is the number in front of the chemical compound

coefficients for the compounds in this reaction are as follows ;

  • H₂S - 2
  • O₂ - 3
  • SO₂ - 2
  • H₂O - 2

therefore, correct option is (a) H₂S:SO₂ = 2:2 and O₂:H₂O = 3:2

Learn more about molar ratio here ;

brainly.com/question/17920577

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4 0
2 years ago
0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction which ensues is: 2Al(OH)3(s) +
Veseljchak [2.6K]

Answer:

The answer to your question is 1.1 moles of water

Explanation:

                     2Al(OH)₃  +   3H₂SO₄   ⇒   Al₂(SO₄)₃  +   6H₂O

                       0.45 mol      0.55 mol                                ?

Process

1.- Calculate the limiting reactant

Theoretical proportion

       Al(OH)₃ / H₂SO₄ = 2/3 = 0.667

Experimental proportion

       Al(OH)₃ / H₂SO₄ = 0.45 / 0.55 = 0.81

From the proportions, we conclude that the limiting reactant is H₂SO₄

2.- Calculate the moles of H₂O

                        3 moles of H₂SO₄ ----------------  6 moles of water

                        0.55 moles of H₂SO₄ -----------    x

                        x = (0.55 x 6) / 3

                        x = 3.3 / 3

                       x = 1.1 moles of water

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3 years ago
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Answer:

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