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3 years ago

What is the wavelength of radiation that has a frequency of 7.2×10^11 s−1 ?

Chemistry

1 answer:

Airida [17]3 years ago

6 0

Explanation:

It is known that relation between wavelength and frequency is as follows.

$\lambda = \frac{c}{\nu}$

where, $\lambda$ = wavelength

c = speed of light = $3 \times 10^{8} m/s$

[/tex]\nu[/tex] = frequency

It is given that frequency is $7.2 \times 10^{11} s^{-1}$ . Hence, putting this value into the above formula and calculate the wavelength as follows.

$\lambda = \frac{c}{\nu}$

$\lambda = \frac{3 \times 10^{8} m/s}{7.2 \times 10^{11} s^{-1}}$

= $0.416 \times 10^{-3} m$

or, = $4.16 \times 10^{-4} m$

Thus, we can conclude that wavelength of given radiation is $4.16 \times 10^{-4} m$ .

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Calculate ΔH (in kJ) for the process Hg2Br2(s) → 2 Hg(l) + Br2(l) from the following information.

Ilia_Sergeevich [38]

Answer : The enthalpy change of reaction is 206.9 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given final reaction is,

$Hg_2Br_2(s)\rightarrow 2Hg(l)+Br_2(l)$ $\Delta H=?$

The intermediate balanced chemical reaction will be,

(1) $Hg(l)+Br_2(l)\rightarrow HgBr_2(s)$ $\Delta H^o_1=-170.7kJ$

(2) $Hg(l)+HgBr_2(s)\rightarrow Hg_2Br_2(s)$ $\Delta H^o_2=-36.2kJ$

First we will reverse the reaction 1 and 2 then adding both the equation, we get :

(1) $HgBr_2(s)\rightarrow Hg(l)+Br_2(l)$ $\Delta H^o_1=+170.7kJ$

(2) $Hg_2Br_2(s)\rightarrow Hg(l)+HgBr_2(s)$ $\Delta H^o_2=+36.2kJ$

The expression for final enthalpy is,

$\Delta H=\Delta H^o_1+\Delta H^o_2$

$\Delta H=(+170.7kJ)+(+36.2kJ)$

$\Delta H=206.9kJ$

Therefore, the enthalpy change of reaction is 206.9 kJ

8 0

3 years ago

Read 2 more answers

when you started the activity, the can was open to the air outside tge can. how did the air pressure inside the can compare to t

aliya0001 [1]

The air pressure inside the can is lower compared to that of outside air pressure.

Explanation:

In general, the air pressure of an already opened can will be the same as the outside pressure.
Since the can is evacuated and remain as vacuum, so there will be no pressure difference in it.
If the can opens, air inside the can push the top and escapes to the outside.
This is due to high pressure experienced outside the can compare to that of lower pressure inside the can and this may even cause can to collapse itself.