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nekit [7.7K]
3 years ago
8

What is the wavelength of radiation that has a frequency of 7.2×10^11 s−1 ?

Chemistry
1 answer:
Airida [17]3 years ago
6 0

Explanation:

It is known that relation between wavelength and frequency is as follows.

                  \lambda = \frac{c}{\nu}

where,        \lambda = wavelength

                       c = speed of light = 3 \times 10^{8} m/s

                  [/tex]\nu[/tex] = frequency

It is given that frequency is 7.2 \times 10^{11} s^{-1}. Hence, putting this value into the above formula and calculate the wavelength as follows.

                    \lambda = \frac{c}{\nu}

                    \lambda = \frac{3 \times 10^{8} m/s}{7.2 \times 10^{11} s^{-1}}

                             = 0.416 \times 10^{-3} m

or,                         = 4.16 \times 10^{-4} m

Thus, we can conclude that wavelength of given radiation is 4.16 \times 10^{-4} m.

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Nataliya [291]

The daughter isotope  : Radon-222 (Rn-222).

<h3>Further explanation</h3>

Given

Radium (Ra-226) undergoes an  alpha decay

Required

The daughter nuclide

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

The decay reaction uses the principle: the sum of the atomic number and mass number before and after decay are the same

Radium (Ra-226) : ₈₈²²⁶Ra

Alpha particles : ₂⁴He

So Radon-226 emits alpha α particles ₂He⁴  , so the atomic number decreases by 2, mass number decreases by 4

The reaction :

₈₈²²⁶Ra ⇒ ₂⁴He + ₈₆²²²Rn

4 0
2 years ago
Use the drop-down menus to select the correct name for each of the organic compounds.
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Answer:

Here's what I get  

Explanation:

CH₃CH₂CH₂CH₂CH₂CH₃ —  hexane

CH₂=CHCH₂CH₂CH₂CH₃ —  hex-1-ene is the preferred IUPAC name (PIN). 1-Hexene is accepted

CH₃C≡CCH₃ —  but-2-yne (PIN); 2-butyne is accepted

CH₃CH(CH₃)CH₂CH₂CH₃ — 2-methylpentane

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Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride
IrinaK [193]

The question is incomplete, here is the complete question:

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 1.1 mL of methane were consumed? Be sure your answer has the correct number of significant digits.

<u>Answer:</u> The volume of hydrogen chloride produced in the reaction will be 4.4 mL

<u>Explanation:</u>

We are given:

Volume of methane gas = 1.1 mL

The chemical equation for the reaction of methane gas and chlorine gas follows:

CH_4(g)+4Cl_2(g)\rightarrow 4HCl(g)+CCl_4(g)

Moles of methane gas = 1 mole

Moles of hydrogen chloride gas = 4 moles

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the volume and number of moles of methane gas

V_2\text{ and }n_2 are the volume and number of moles of hydrogen chloride

We are given:

V_1=1.1mL\\n_1=1mol\\V_2=?L\\n_2=4mol

Putting values in above equation, we get:

\frac{1.1}{1}=\frac{V_2}{4}\\\\V_2=\frac{1.1\times 4}{1}=4.4mL

Hence, the volume of hydrogen chloride produced in the reaction will be 4.4 mL

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Answer:

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Explanation:

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