According to the model, the year will the population exceed 470 million is 2060
What is the first step to take?
The first step in this case is to use the model to compute the population figure in each year as shown below:
N = 3.21t + 277.3
Year 2020:
t=20
N = 3.21(20) + 277.3
N=341.50
Year 2025:
t=25
N = 3.21(25) + 277.3
N= 357.55
Year 2030:
t=30
N = 3.21(30) + 277.3
N=373.60
Year 2035:
t=35
N = 3.21(35) + 277.3
N= 389.65
Year 2060:
t=60
N = 3.21(60)+ 277.3
N= 469.90
Year 2065:
t=65
N = 3.21(65)+ 277.3
N= 485.95
Since all the years given do not give the correct year, let us equate the target population figure to the model and solve for t
470= 3.21t + 277.3
470-277.3=3.21t
192.70=3.21t
t=192.70/3.21
t=60.03(approximately 2060)
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Wheres the table?? You said “the table below” and what are you asking for? I can always answer in the comments section
Answer:
Hi use the attached formula to calculate the midpoints
Attached also is an example
Hope this helps
The solution set for the last equation represents the set of all days when the towns have the same average high temperature.
- The hotness of matter or radiation is expressed by the physical quantity known as temperature. The average air temperature for a specific time period, often a day, a month, or a year, as measured by a thermometer that has been properly exposed.
- P(t) is the average high temperature, in degrees Celsius, of Paityn's town on t days.

- V(t) is the average high temperature, in degrees Celsius, of Vince's town on t days.

- So, P(t) = V(t) represents the set of all the days when both towns have the same average high temperature.
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