Water supply.
Food production.
Housing and shelter.
Sanitation and waste management.
Energy development.
Transportation.
Answer:
transfer function = 500 / 3 = 166.67 rpm /V
Explanation:
Answer: N has to be lesser than or equal to 1666.
Explanation:
Cost of parts N in FPGA = $15N
Cost of parts N in gate array = $3N + $20000
Cost of parts N in standard cell = $1N + $100000
So,
15N < 3N + 20000 lets say this is equation 1
(cost of FPGA lesser than that of gate array)
Also. 15N < 1N + 100000 lets say this is equation 2
(cost of FPGA lesser than that of standardcell)
Now
From equation 1
12N < 20000
N < 1666.67
From equation 2
14N < 100000
N < 7142.85
AT the same time, Both conditions must hold true
So N <= 1666 (Since N has to be an integer)
N has to be lesser than or equal to 1666.
I guess this is the answer, thanks for giving out stuff, kind stranger!
Answer:
The power absorbed by the 60 ohm resistor is 1.064 W
Explanation:
When there's no load connected to the source (open circuit) its voltage output is ideal, since there won't be any voltage drop across it's internal resistance. When there's a shor circuit, the only load is the internal resistance of the source, so we can use Ohm's law to compute the internal resistance, as shown bellow:
Rinternal = Vopenload/Ishortcircuit
Rinternal = 8/200 = 0.04 Ohm
When we connect a load to this source, the total load we'll be the external resistance plus the internal resistance. We can now compute the curent flow when there's a 60 Ohm resistance connected to the terminals of the source by using Ohm's law again:
I = Vsource/(Rexternal + Rinternal)
I = 8/(60 + 0.04) = 8/(60.04) = 0.1332 A
The absorbed power is the product of the voltage across the terminals of the resistor and the current that goes through it. The current is the one we calculated above and the voltage across it's terminals is given by I*R, so the power output is:
P = I*Vresistor
P = I*(I*R)
P = R*I^2 = 60*(0.1332)^2 = 1.064 W