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Molodets [167]
3 years ago
6

When circuit switching is used, what is the maximum number of circuit-switched users that can be supported? Explain your answer

in your own words.
Engineering
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer & Explanation:

When circuit switching is used, maximum 15 circuit switched user can be supported. Because for each of the user is allocated 10 MBPS bandwidth, and given link capacity is 150 MBPS.

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The two windings of transformer is: a)- Conductively linked. b)- Not linked at all. c)- Inductively linked d)- Electrically link
kondor19780726 [428]

The two windings of transformer is c)- Inductively linked

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The importance of reading a circuit diagram to interpret a wiring diagram?
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Answer:

The ability to read electrical schematics is a really useful skill to have. To start developing your schematic reading abilities, it's important to memorize the most common schematic symbols. ... You should also be able to get a rough idea of how the circuit works, just by looking at the schematic.

Explanation:

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2 years ago
Water that has evaporated returns to earth as
denis23 [38]

Answer:

rain

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3 years ago
Read 2 more answers
**Please Help, ASAP**
Novay_Z [31]

Explanation:

We need to rearrange the following formula for the values given in parenthesis.

(1) x+xy = y, (x)

taking x common in LHS,

x(1+y)=y

x=\dfrac{y}{1+y}

(2) x+y = xy, (x)

Subrtacting both sides by xy.

x+y-xy = xy-xy

x+y-xy = 0

x-xy=-y

x(1-y)=-y

x=\dfrac{-y}{1-y}

(3) x = y+xy, (x)

Subrating both sides by xy

x-xy = y+xy-xy

x(1-y)=y

x=\dfrac{y}{1-y}

(4) E = (1/2)mv^2-(1/2)mu^2, (u)

Subtracting both sides by (1/2)mv^2

E-(1/2)mv^2 = (1/2)mv^2-(1/2)mu^2-(1/2)mv^2

E-(1/2)mv^2 =-(1/2)mu^2

So,

2(E-\dfrac{1}{2}mv^2)=-mu^2\\\\u^2=\dfrac{-2}{m}(E-\dfrac{1}{2}mv^2)\\\\u=\sqrt{\dfrac{-2}{m}(E-\dfrac{1}{2}mv^2)}\\\\u=\sqrt{\dfrac{2}{m}(\dfrac{1}{2}mv^2-E)}

(5) (x^2/a^2)-(y^2/b^2) = 1, (y)

\dfrac{x^2}{a^2}-1=\dfrac{y^2}{b^2}\\\\y^2=b^2(\dfrac{x^2}{a^2}-1)\\\\y=b\sqrt{\dfrac{x^2}{a^2}-1}

(6) ay^2 = x^3, (y)

y^2=\dfrac{x^3}{a}\\\\y=\sqrt{\dfrac{x^3}{a}}

Hence, this is the required solution.

3 0
3 years ago
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