Answer:
The stiffness of an axially loaded bar is (EA)/L
The flexibility of an axially loaded bar is L/(EA)
The stiffness of a torsionally loaded round bar is (GJ)/L
The flexibility of a torsionally loaded round bar is L/(GJ)
Explanation:
For axially loaded round bar, ExA measures, what is known as, the axial rigidity of the round bar. "E" is defined as the Young's modulus which is the property of the bar that measures the stiffness of the bar itself and is meausred in Pascals. A is the area of the cross section of the bar. L is the entire length of the bar. Multiple the Young's modulus with the cross sectional area and divide the value by the length which will give the stiffness of the axially loaded bar. The inverse of this equation will give you the flexibility.
For a Torsionally loaded round bar, the formula is a bit different. G is the modulus rigidity of the bar and J is the Torsional constant. GJ is calculated by multiplying the applied torque with the length od the bar and dividing the result by the angle of the twist. Dividing the result by the length will give the stiffness. Inverse of the equation measuring stiffness gives the flexibility
Answer:
Technician B
Explanation:
Resistance, where V is the voltage and I is the current in amps
Therefore,
Power=VI=12*12=144 W
Therefore, the power is 144 W and resistance is 1 Ohm. This implies that technician A is wrong while technician B is correct
Answer:
(a)The mass flow rate =
2.297×10^6 lb/HR
(b)the rate of heat transfer =2700.847×10^6Btu/hr
(c)thermal efficiency is 37.025%
Check attachments for calculation
37 students in the class
18 Girls and 19 Boys
Answer:
You can do it by your self, since you are smart enough.
Explanation:
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