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zhuklara [117]
3 years ago
5

Why did Rutherford choose alpha particles in his experiment?

Chemistry
1 answer:
Georgia [21]3 years ago
5 0
Rutherford used gold for his scattering experiment because gold is the most malleable metal and he wanted the thinnest layer as possible. The goldsheet used was around 1000 atoms thick. Therefore, Rutherford selected a Gold foil in his alpha scatttering experiment.
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NaOH + HCl -&gt;<br> Fe + HCl -&gt;
vfiekz [6]

Answer:

This is an oxidation-reduction (redox) reaction:

2 HI + 2 e- → 2 H0 (reduction)

Fe0 - 2 e- → FeII (oxidation)

HCl is an oxidizing agent, Fe is a reducing agent.

Reactants:

Fe

Names: Iron source: wikidata, accessed: 2019-09-07, Fe source: wikidata, accessed: 2019-09-07, Element 26 source: wikidata, accessed: 2019-09-07... show more

HCl – Chlorane source: wikipedia, accessed: 2019-09-27, Hydrogen chloride source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02

Other names: Hydrochloric acid sourc2 2019-09-27source: NIOSH NPG, accessed: 2019-09-02, M source: wikipedia, accessed: 2019-09-27, Uriatic acid source: wikipedia, accessed: 2019-09-27... show more

Appearance: Colorless, transparent liquid, fumes in air if concentrated source: wikipedia, accessed: 2019-09-27; Colorless gas source: wikipedia, accessed: 2019-09-27; Colourless compressed liquefied gas with pungent odour source: ICSC, accessed: 2019-09-04; Colorless to slightly yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.] source: NIOSH NPG, accessed: 2019-09-02

Products:

FeCl2 – Iron(II) chloride source: : 2019-09-27source: ICSC, accessed: 2019-09-04, Iron dichloride source: wikipedia, accessed: 2019-09-27source: ICSC, accessed: 2019-09-04

Other names: Ferrous chloride source 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04, Rokühnite source: wikipedia, accessed: 2019-09-27, [FeCl3] source: wikidata, accessed: 2019-09-02, FeCl3 source: wikidata, accessed: 2019-09-02

Appearance: Tan solid (anhydrous) | Pale green solid (di-tetrahydrate) source: wikipedia, accessed: 2019-09-27; White-to-light-green hygroscopic crystals source: ICSC, accessed: 2019-09-04

H2

Names: Dihydrogen source 2019-09-07, Hydrogen source: ICSC, accessed: 2019-09-04source: wikidata, accessed: 2019-09-07, H2 source: wikidata, accessed: 2019-09-07... show more

Appearance: Odourless colourless compressed gas source: ICSC, accessed: 2019-09-04

Hope this helps

5 0
3 years ago
HBr can be added to an alkene in the presence of peroxides (ROOR). What function does the peroxide serve in this reaction
RSB [31]

Answer:

Radical chain initiator

Explanation:

The peroxide here serves as a radical chain initiator. In the field of chemistry the radical initiatives are those substances that are used in industrial processes like polymer synthesis. These initiatives have weak bonds generally and they're mostly used to create free radicals. These radicals are atoms that have odd numbers of electrons. Peroxide is an example of such.

6 0
3 years ago
Dissolving 5.28 g of an impure sample of calcium carbonate in hydrochloric acid produced 1.14 L of carbon dioxide at 20.0 °C and
swat32

Answer:

\%\ mass\ of\ CaCO_3=93.37\ \%

Explanation:

Given that:

Pressure = 791 mmHg

Temperature = 20.0°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (20 + 273.15) K = 293.15 K  

T = 293.15 K  

Volume = 100 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637 L.mmHg/K.mol  

Applying the equation as:

791 mmHg × 1.14 L = n × 62.3637 L.mmHg/K.mol  × 293.15 K  

⇒n of CO_2 produced =  0.0493 moles

According to the reaction:-

CaCO_3 + 2 HCl\rightarrow CaCl_2 + H_2O + CO_2

1 mole of carbon dioxide is produced 1 mole of calcium carbonate reacts

0.0493 mole of carbon dioxide is produced 0.0493 mole of calcium carbonate reacts

Moles of calcium carbonate reacted = 0.0493 moles

Molar mass of CaCO_3 = 100.0869 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0493\ mol= \frac{Mass}{100.0869\ g/mol}

Mass_{CaCO_3}=4.93\ g

Impure sample mass = 5.28 g

Percent mass is percentage by the mass of the compound present in the sample.

\%\ mass\ of\ CaCO_3=\frac{Mass_{CaCO_3}}{Total\ mass}\times 100

\%\ mass\ of\ CaCO_3=\frac{4.93}{5.28}\times 100

\%\ mass\ of\ CaCO_3=93.37\ \%

3 0
3 years ago
NOOO LINNKKKSSS
Elena L [17]
The answer is D I hope this helps you !
3 0
3 years ago
Read 2 more answers
What is the total ionic equation for cuso4+2naoh&gt;&gt;cu(oh)2+na2so4
iVinArrow [24]

Answer:

CuSO4 + 2 NaOH = Cu(OH)2 + Na2SO4

3 0
3 years ago
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