I honestly don’t know the answer to this one
Answer:
Q = 12.38
Explanation:
The Nernst equation is given as; Ecell = E°cell - (2.303RT/nF) log Q ;where Q is the reaction quotient.
The reaction quotient, Q in a reaction, is the product of the concentrations of the products divided by the product of the concentrations of the reactants.
In an electrochemical cell, Q is the ratio of the concentration of the electrolyte at the anode to that of the electrolyte at the cathode.
Q = [anode]/[cathode]
therefore , Q = 0.052/0.0042 = 12.38
First, you need to find:
One mole of

is equivalent to how many grams?
Well, for this you have to look up the periodic table. According to the periodic table:
The atomic mass of Calcium Ca = 40.078 g (See in group 2)
The atomic mass of <span>Chlorine Cl = 35.45 g (See in group 17)
</span>
As there are two atoms of Chlorine present in

, therefore, the atomic mass of

would be:
Atomic mass of

= Atomic mass of Ca + 2 * Atomic mass of Cl
Atomic mass of

= 40.078 + 2 * 35.45 = 110.978 g
Now,
110.978 g of

= 1 mole.
75.9 g of

=

= 0.6839 moles.
Hence,
The total number of moles in 75.9g of

= 0.6839 moles
According to <span>Avogadro's number,
1 mole = 1 * </span>

molecules
0.6839 moles = 0.6839 *

molecules =

molecules
Ans: Number of molecules in 75.9g of
=
molecules
-i
The molar mass (atomic weight ) of sodium is 23.0 grams/mole and the molar mass of sodium azide, NaN3 , is the mass of sodium, 23.0 gram/mole added to the molar mass of three atoms of nitrogen (14.0 x 3 = 42 gram/mole) which equals 65.0 grams/mole. The percentage of sodium is 23.0 /65.0 x 100 % = 35 %
Answer:
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