Question

How much heat must your body transfer to 500.0g of water to heat it from 25.0°C to body temperature, 37.0°C?

Answer 1

Answer : The heat your body transfer must be, 25.1 kJ

Explanation :

Formula used :

$Q=m\times c\times \Delta T$

or,

$Q=m\times c\times (T_2-T_1)$

where,

Q = heat = ?

m = mass of water = 500.0 g

c = specific heat of water = $4.18J/g^oC$

$T_1$ = initial temperature  = $25.0^oC$

$T_2$ = final temperature  = $37.0^oC$

Now put all the given value in the above formula, we get:

$Q=500.0g\times 4.18J/g^oC\times (37.0-25.0)K$

$Q=25080J=25.1kJ$

Therefore, the heat your body transfer must be, 25.1 kJ