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LiRa [457]
3 years ago
5

What the answer solve for a: 9 = ca

Mathematics
1 answer:
kompoz [17]3 years ago
8 0

Answer:

a = 9/c

Step-by-step explanation:

We want to isolate a.  To do this, divide both sides of the given equation by c:

9      ca

---- = -----

 c        c

This yields

a = 9/c

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What is ∛2197? Explain how you got your answer.
user100 [1]

Answer:

13

Step-by-step explanation:

We need to write our answer in exponential form. Ask yourself the question, "What times itself 3 times will give you 2197?" Your answer is 13^{3}. This will go inside of your cube root. You now have \sqrt[3]{13^{3} }. Since there's a power of 3 and a cube root, those cancel each other out, and your answer is 13.

5 0
3 years ago
Read 2 more answers
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
Which system of equations will yield the same solution as x-y=3 2x-3y=-1​
laiz [17]

Answer: Is there some answer choices? Because I can't help if I  don't have any choices.

Step-by-step explanation:

5 0
3 years ago
A diagonal of a square is 36 feet long. What is the area of the square?
Rzqust [24]
So you can you the Pythagorean theorem to solve this problem.

if each side of the square is a certain length x, then the square is made up of two right triangles.

the sides adjacent to the right angle are length x while the hypoteneus is the diagonal whcih measures 36 feet.

a^2 + b^2 = c^2

x^2 + x^2 = 36^2

2x^2 = 1296

x^2 = 648

x = 25.456

area of a square = x^2 = 648 ft^2
3 0
3 years ago
3x + 6y = 14<br>2x + 8y = 2​
solmaris [256]

Step-by-step explanation:

x=14-6y/3

substituting x=14-6y/3 into eqn 2

2(14-6y/3)+8y=2

multiplying through by 3

2(14-6y/3)×3 +8y×3=2×3

2(14-6y)+24y=6

28-12y+24y=6

28-12y=6

28-6=12y

22=12y

22/12=y

finding x

2x+8(22/12)=2

2x+44/3=2

2x=2-44/3

x=(-38/3)/2

×=-38/6

7 0
2 years ago
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