Question

Two thin conducting plates, each 25.0 cm on a side, are situated parallel to one another and 5.0 mm apart. If 10^?11 electrons are moved from one plate to the other,what is the electric field between the plates?

Answer 1

Answer:$E=2.9\times 10^3\ N/C$

Explanation:

Given

Side of square plate $L=25\ cm$

distance between plates $d=5\ mm$

no of electron $n=10^{11}\ electrons$

electron charge $e=1.6\times 10^{-19}\ C$

$\epsilon _0=8.85\times 10^{-12}$

Electric field between plates  is given by

$E=\frac{\sigma }{\epsilon _0}$

$E=\frac{\frac{Q}{A}}{\epsilon _0}$

$E=\frac{ne}{A\epsilon _0}$

$E=\frac{10^{11}\times 1.6\times 10^{-19}}{0.25^2\times 8.85\times 10^{-12}}$

$E=2.9\times 10^3\ N/C$