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Sloan [31]
2 years ago
10

Mr Jones launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how far south does the arrow

travel. (Step 2, you need the previous questions answer to answer correctly
a. 118.4 m south
b 1936 m south
C 2 m south
d 640 m south​
Physics
1 answer:
DanielleElmas [232]2 years ago
4 0

Answer:c

Explanation:its the answer because its the answer

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A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by
Vlad [161]

Answer: D. 5cm

Explanation:

Given the following :

Focal length (f) = - 6.0 cm

Height of object = 15.0cm

Distance of object from mirror (u) = 12.0cm

Height of image produced by the mirror =?

Firstly, we calculate the distance of the image from the mirror.

Using the mirror formula

1/f = 1/u + 1/v

1/v = 1/f - 1/u

1/v = 1/-6 - 1/12

1/v = - 1/6 - 1/12

1/v = (- 2 - 1) / 12

1/v = - 3 / 12

v = 12 / - 3

v = - 4

Using the relation :

(Image height / object height) = (- image distance / object distance)

Image height / 15 = - (-4) / 12

Image height / 15 = 4 / 12

Image height = (15 × 4) / 12

Image height = 60 / 12

Image height = 5cm

6 0
3 years ago
A 0.500-V potential difference is maintained across a 1.50-m length of tungsten wire that has a cross-sectional area of 0.800 mm
Genrish500 [490]

Answer:

5.95 A

Explanation:

From the question

R = ρL/A..................... Equation 1

Where R = resistance of the tungsten wire, ρ = Resistivity of the tungsten wire, L = length, A = cross sectional area.

Given: L = 1.5 m, A = 0.8 mm² = 0.8×10⁻⁶ m, ρ = 5.60×10⁻⁸ Ω.m

Substitute these values into equation 1

R = 1.5(5.60×10⁻⁸)/0.8×10⁻⁶

R = 0.084 Ω.

Finally, using Ohm law,

V = IR

Where V = Voltage, I = current

Make I the subject of the equation

I = V/R............... Equation 2

I = 0.5/0.084

I = 5.95 A

4 0
3 years ago
Roman citizenship guaranteed Paul:
deff fn [24]
<span>protection from injustices</span>
3 0
3 years ago
Read 2 more answers
what is the net force of a 6 kg object that goes from a velocity of 0.5 m/s to a velocity of 3 m/s over the course of 1.5 second
baherus [9]

Answer:

∑F = 10.2 N

Explanation:

We have:

Initial velocity: 0.5 m/s

Final velocity: 3 m/s

Time: 1.5 s

We have all of the components needed to calculate acceleration. Let's do that, shall we?

a = vf-vo/t

a = 2.5/1.5

a = 1.7 m/s^{2}

Now, look at the Net Force equation:

∑F = ma

Plug in the variables, to get:

∑F = (6)(1.7)

∑F = 10.2 N (You can round this according to significant digits)

3 0
3 years ago
If a spring is stretched 4m from its starting length when 20n of force is applied, then how much work (in joules) is done by the
lys-0071 [83]

ANSWER:

250 J

STEP-BY-STEP EXPLANATION:

F = 20N is required to stretch the spring by 4 meters

We know that the force is equal to:

F=k\cdot x

We solve for k (spring constant):

k=\frac{F}{x}=\frac{20}{4}=5\text{ N/m}

The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:

\begin{gathered} W=\frac{1}{2}k\cdot x^2 \\ \text{ Replacing} \\ W=\frac{1}{2}\cdot5\cdot10^2 \\ W=250\text{ J} \end{gathered}

The work required is 250 joules.

5 0
1 year ago
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