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hoa [83]
3 years ago
5

What percentage of stars do kepler scientists suggest host earth size planets?

Physics
2 answers:
Nonamiya [84]3 years ago
6 0
The answer is D. 5.4%.

Moreover, 48 planet candidates were found in the habitable zones of surveyed stars. The Kepler team estimated that 5.4% of all stars host Earth-size planet candidates, and that 17% of all stars have multiple planets.
bezimeni [28]3 years ago
5 0
The answer is C. hope i helped
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According to Boyles’ law, PV = constant. If a graph is plotted with the pressure P against the volume V, the graph would be a(n)
Hunter-Best [27]

Answer:

C. hyperbola

Explanation:

From Boyle's law:

PV = k, where k is a constant

Solving for P:

P = k / V

At first glance, this equation doesn't fit any of the options.  But when you graph it, you can see that it's actually a <em>rotated</em> hyperbola.

4 0
3 years ago
Read 2 more answers
if you double the magnitude of a vector, does it follow that the magnitude of the components double? Give example.
jarptica [38.1K]

Answer:

The magnitude of the vector clearly doubles if each of its components is doubled.

Explanation:

8 0
3 years ago
Using the conversion factor from eV (electron volts) to joules, determine which energy line for an electron dropping from one en
Tom [10]

Explanation:

Wavelength in an emission spectrum,  \lambda=435\ nm=435\times 10^{-9}\ m  

The energy of an electron is given by :

E=\dfrac{hc}{\lambda}

Where

h is the Planck's constant

c is the speed of light

For 435 nm, the energy of the electron will be :

E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8\ m/s}{435\times 10^{-9}}

E=4.57\times 10^{-19}\ J

We know that 1\ eV=1.6\times 10^{-19}\ J

So, E=\dfrac{4.57\times 10^{-19}}{1.6\times 10^{-19}}

So, E = 2.86 eV

The energy of the electron dropping from one energy level is 2.86 eV. We know that,

\dfrac{hc}{\lambda}=E_{n_2}-E_{n_1}

From the given energy levels :

E_5-E_2=-0.544-(-3.403)

E_5-E_2=2.859\ eV

So, the transition must be from E₅ to E₂. Hence, this is the required solution.                                             

5 0
4 years ago
Read 2 more answers
I need help with number 23!! Please
Juliette [100K]
Ah hah !  There's an easy way and a hard way to do this one.
If it's OK with you, I'm gonna do it the easy way, and not even
talk about the hard way !

First, let's look at a few things in this question.

-- "gravitational force between a planet and a mass"
    This is just a complicated way to say "How much does the mass weigh ?"
    That's what we have to find.

-- If we know the mass, how do we find the weight ?
   Multiply the mass by the acceleration of gravity there.
   Weight = (mass) x (gravity) .

-- Do we know the acceleration of gravity on this dark mysterious planet ?
    We do if we read the second line of the question !  
    It's right there ... 8.8 m/s² .

-- We know the mass.  We know gravity.  And we know that
    if you multiply them, you get the weight (forced of gravity).

I'm pretty sure that you can do the rest of the solution now.

weight = (mass) x (gravity)

Weight = (17 kg) x (8.8 m/s²)

Multiply them:

Weight = 149.6  kg-m/s²

That complicated-looking unit is the definition of a Newton !

So the weight is  149.6 Newtons.  That's the answer.  It's choice-A.
It's about 33.6 pounds.

When this mass is on the Earth, it weighs about 37.5 pounds.
But when it's on this planet, it only weighs about 33.6 pounds.
That's because gravity is less on this planet. (8.8 there, 9.8 on Earth)
3 0
3 years ago
Fill in the blanks to complete the statements.
Murljashka [212]

Answer:

When an object changes speed (increases/decreases) it results in acceleration/de acceleration, its velocity also changes.

Explanation:

Acceleration is the rate of change in velocity.An object can accelerate when speed increases, decreases or direction changes. All these instances involves a change in velocity.Velocity is a vector quantity thus it has magnitude and the direction.Acceleration due to change in direction is centripetal acceleration.The expression for finding acceleration is;

a=change in velocity/change in time

a=Δv/Δt in m/s²

3 0
3 years ago
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