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3 years ago

True or false? Potential difference is measured in joules

Physics

2 answers:

kirill [66]3 years ago

7 0

$\huge\colorbox{purple}A\colorbox{blue}n\colorbox{purple}s\colorbox{blue}w\colorbox{purple}e\colorbox{blue}r$

$\color{Violet}\rm{Hopeithelps!シ︎}$

uhm i think TRUE✨

I'm not sure hehe.

If one joule of energy is required to move one coulomb of charge through a component in a circuit, then the potential difference across the component is one volt (or 1 joule per coulomb).

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“The Lord your God is in your midst — a warrior bringing victory. He will create calm with his love; he will rejoice over you with singing.” — Zephaniah 3:17 ❤

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Lyrx [107]3 years ago

7 0

True it’s measured in either joules or volts

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In a certain experiment, a radio transmitter emits sinusoidal electromagnetic waves of fre- quency 110.0 MHz in opposite directi

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To solve the problem it is necessary to take into account the concepts related to frequency depending on the wavelength and the speed of light.

By definition we know that the frequency is equivalent to,

$f=\frac{c}{\lambda}$

where,

c= Speed of light

$\lambda = Wavelength$

While the wavelength is equal to,

$\lambda = \frac{2L}{n}$

Where,

L = Length

n = Number of antinodes/nodes

PART A) For the first part we have that our wavelength is 110MHz, therefore

$\lambda = \frac{c}{f}$

$\lambda = \frac{3*10^8}{11*10^6}$

$\lambda = 1.36m$

Therefore the distance between the nodal planes is 1.36m

PART B) For this part we need to find the Length through the number of nodes (8) and the wavelength, that is,

$\lambda'=\frac{2L}{n}$

$L = \frac{\lambda n}{2}$

$L = \frac{8*2.72}{2}$

$L = 10.90m$

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3 years ago

An inclined plane has a velocity ratio of 2 and efficiency of 95%. it is used to raise a load of 400newtons. determine mechanica

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Answer:

1.9

Explanation:

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3 years ago

A solid metal ball of radius 1.5 cm bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing a

blsea [12.9K]

We have that the electric field at the center of the metal ball due only to the charges on the surface of the metal ball is

$E=7*10^{9}N/C$

From the question we are told that

A solid metal ball of radius 1.5 cm

bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing

uniformly distributed charge of -7 nC

The distance between the centers of the balls is 9 cm

Generally the equation for the electric field is mathematically given as

$E=\frac{kq_2}{d^2}\\\\E=\frac{(9*10^9)7*10^{-2}}{9*10^{-2}}\\\\$

$E=7*10^{9}N/C$

For more information on this visit

brainly.com/question/21811998

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3 years ago

The density of Mercury is 1.36 × 10 by 4 Kgm - 3 at 0 degrees. Calculate its value at 100 degrees and at 22 degrees. Take cubic

Drupady [299]

a) Density at 100 degrees: $1.34\cdot 10^4 kg/m^3$

Explanation:

The density of mercury at 0 degrees is $d=1.36\cdot 10^4 kg/m^3$

Let's take 1 kg of mercury. Its volume at 0 degrees is

$V=\frac{m}{d}=\frac{1 kg}{1.36\cdot 10^4 kg/m^3}=7.35\cdot 10^{-5} m^3$

The formula to calculate the volumetric expansion of the mercury is:

$\Delta V= \alpha V \Delta T$

where

$\alpha=180\cdot 10^{-6} K^{-1}$ is the cubic expansivity of mercury

V is the initial volume

$\Delta T$ is the increase in temperature

In this part of the problem, $\Delta T=100 C-0 C=100 C=100 K$

So, the expansion is

$\Delta V= \alpha V \Delta T=(180\cdot 10^{-6} K^{-1})(7.35\cdot 10^{-5} m^3)(100 K)=1.3\cdot 10^{-6} m^3$

So, the new density is

$d'=\frac{m}{V+\Delta V}=\frac{1 kg}{7.35\cdot 10^{-5} m^3+1.3\cdot 10^{-6} m^3}=1.34\cdot 10^4 kg/m^3$

b) Density at 22 degrees: $1.355\cdot 10^4 kg/m^3$

We can apply the same formula we used before, the only difference here is that the increase in temperature is

$\Delta T=22 C-0 C=22 C=22 K$

And the volumetric expansion is

$\Delta V= \alpha V \Delta T=(180\cdot 10^{-6} K^{-1})(7.35\cdot 10^{-5} m^3)(22 K)=2.9\cdot 10^{-7} m^3$

So, the new density is

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3 years ago

a rock is vertically upward with a velocity of 10 m/s. calculate the maximum height it reaches and time taken to reach that heig

lina2011 [118]

Answer:

maximum height: p(t) = Vo * t - 1/2 * g * t^2

p’(t) = v(t) = 0 = Vo - g*t. So, maximum height occurs when t = Vo / g

p(Vo / g) = Vo^2/g - 1/2 * g * (Vo/g)^2

Vo = 10 m / s. Let’s approximate g = 10 m / s^2

p(Vo / g) = 10^2 / 10 - 1/2 * 10 * (10/10)^2 = 10 - 5 = 5 meters (approximately)

Calculation of time:

v = u + gt

0 = 10√2 + (-10)t

-10√2 = -10t

2 = √2s

8 0

3 years ago

True or false? Potential difference is measured in joules​

True or false? Potential difference is measured in joules