Answer:
a.c.n.e (join the letters together without full stops. i need to type like this as brainly does not allow me to type that word)
Explanation:
An excess of sebum combined with dead skin cells can block pores and cause blemishes such as blackheads and pimples.
The correct option is IT CAN FORM FOUR COVALENT BONDS.
Carbon is capable of forming four covalent bond in order to attain the octet form, this gives it the ability to combine with different elements in different ways. The ability to combine with different elements makes carbon to be abundant on the earth, because it is found in variety of different substances.
Answer:
<u> The following four traits are -: </u>
- <u>Pedigree 1 -</u> A recessive trait (autosomal recessive) is expressed by pedigree 1.
- <u>Pedigree 2- Recessive inheritance is defined by Pedigree 2. </u>
- <u>Pedigree 3</u> - The inheritance of the dominant trait (autosomal dominant) is illustrated by Pedigree 3.
- <u>Pedigree 4-</u> An X-like dominant trait is expressed by Pedigree 4.
Explanation:
<u>Explaination of each pedigree chart</u>-
- Pedigree 1 demonstrates the <u>recessive trait </u>since their children have been affected by two unaffected individuals. If the characteristics were X-linked, in order to have an affected daughter, I-1 would have to be affected.
In this, both parents are autosomal recessive trait carriers, so the child will be affected by a 1/4 (aa) - <u> Recessive inheritance</u> is defined by <u>Pedigree 2</u>. This is<u> X-related inheritance as autosomal recessive</u> inheritance has already been accounted for in part 1. This inference is confirmed by evidence showing that the father (I-1) is unaffected and that only the sons exhibit the characteristic in generation II, suggesting that the mother must be the carrier. The individual I-2 is a carrier for this X-linked trait. A typical Xa chromosome is attached to the unaffected father (I-1), so the chance of carrier II-5 is 1/2. Probability of an affected son = 1/2 (probability II-5 is a carrier) x 1/2 (probability II -5 contributes (
) x 1/2 (probability of Y from father II-6) = 1/8. An affected daughter's likelihood is 0 because a typical
must be contributed by II-6. - The inheritance of the<u> dominant trait</u> is demonstrated by <u>Pedigree 3 </u>because affected children still have affected parents (remember that all four diseases are rare). The trait must be <u>autosomal dominant</u> because it is passed down to the son by the affected father. There is a 1/2 risk that the heterozygous mother (II-5) would pass on mutant alleles to a child of either sex for an autosomal dominant feature.
- <u>Pedigree 4</u> is an <u>X-linked dominant function</u> characterized by the transmission to all of his daughters from the affected father but none of his son. On the mutant X chromosome, the father (I-1) passes on to all his daughters and none of his sons. As seen by his normal phenotype, II-6 therefore does not bear the mutation. An affected child's likelihood is 0.
In the question the pedigree chart was missing ,hence it is given below.
Carbon fixation is the process in which plants remove the carbon from atmospheric carbon dioxide and turn it into organic molecules like carbohydrates.
Because different type of plants are located in regions with different conditions they are different types of carbon fixation. Plants that live in arid regions need to conserve water, while plants that live in more moist conditions will not need to conserve water.
The carbon fixation in C3 plants is one-step process. An oxidation reaction occurs because of the enzyme RuBisCo. During the oxidation some of the energy used in photosynthesis is lost in a process known as photorespiration.
Polysaccharides at made up of 2 or more monosaccharides bonded together