Vertical axis is the y values. It is called range of function based from the graph. The horizontal axis, x value, is called the domain.
1, 2, 3, 4, 5, 3, 4, 5, 4, 5, 5, 8, 1 ⇒ Range of DVDs owned.
If the range needed is in relation to mean, median, and mode, then the range is the difference between the largest and the smallest data.
First, we need to arrange it from least to greatest.
1, 1, 2, 3, 3, 4, 4, 4, 5, 5, 5, 5, 8
Then, we find the difference of the largest value from the smallest value.
8 - 1 = 7.
7 is the range of the data set.
Answer:
Step-by-step explanation:
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Answer:
Step-by-step explanation:
You make 4 into 4/1 and then raise it to 8/2. then you divide across, if im right.
<u>Step-by-step explanation:</u>
Here we have , an expression c + 2 . We need to find that What happens to the value of the expression c+2 as c increases .Let's find out:
Let y = c + 2 or
, where y is dependent on c and y is directly proportional to c i.e. as value pf c increase value of y increases . Let's have some example as
At c = 1
![y = c+2](https://tex.z-dn.net/?f=y%20%3D%20c%2B2)
⇒ ![y = c+2](https://tex.z-dn.net/?f=y%20%3D%20c%2B2)
⇒ ![y = 1+2](https://tex.z-dn.net/?f=y%20%3D%201%2B2)
⇒ ![y = 3](https://tex.z-dn.net/?f=y%20%3D%203)
At c = 2
![y = c+2](https://tex.z-dn.net/?f=y%20%3D%20c%2B2)
⇒ ![y = c+2](https://tex.z-dn.net/?f=y%20%3D%20c%2B2)
⇒ ![y = 2+2](https://tex.z-dn.net/?f=y%20%3D%202%2B2)
⇒ ![y = 4](https://tex.z-dn.net/?f=y%20%3D%204)
So , value of expression c+2 increases with value of c . Also , expression c+2 is a straight line having a slope of 1 and a y-intercept of 2 .
u = 1+3e<span>-x</span>
so that (Don't forget to use the chain rule on e<span>-x</span>.)
du = 3e<span>-x</span>(-1) dx = -3e<span>-x</span> dx ,
or
(-1/3)du = e<span>-x</span> dx .
However, how can we replace the term e<span>-3x</span> in the original problem ? Note that
.
From the u-substitution
u = 1+3e<span>-x</span> ,
we can "back substitute" with
e<span>-x</span> = (1/3)(u-1) .
Substitute into the original problem, replacing all forms of x, getting
(Recall that (AB)C = AC BC .)