Alright! In order to do number 3, you first have to simply what you have. So:
√4x[12-√(10-6)] → √4x[12 ÷ √4]
Now, to find the square root of a number you simply ask yourself, "What number times itself will give me that number?". So, the number two times itself is equal to 4. So:
√4 = 2. Plug in this value for √4.
2x[12 ÷ 2] → 2x6
Multiply:
2x6 = 12
The 12th term in the sequence is -26.
Given,
B (n) = -4 – 2(n – 1)
We have to find the 12th term in the sequence:
To find the nth term in an arithmetic sequence:
An arithmetic sequence's nth term is determined by the formula a = a + (n - 1)d. The common difference, or d, is the difference between any two consecutive terms in an arithmetic series; it can be calculated by deducting any pair of terms starting with a and an+1.
Here,
First term, a = -4
Common difference, d = -2
nth term = 12
Now, let’s find 12th term
B(n) = -4 -2(n – 1)
B(12) = -4 – 2(12 – 1)
B(12) = -4 -2(11)
B(12) = -4 -22
B(12) = -26
That is, the 12th term in the sequence is -26.
Learn more about arithmetic sequence here:
brainly.com/question/11570734
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Insert y in the second equation and solve for x:
4x+(x^2-8)=-8
4x+x^2-8=-8
4x+x^2=0
x^2+4x=0
x = -4
Now you insers this x-value in the first or second equation (i use the first):
y=(-4)^2-8=16-8=8
Therefore the conclusion must be x=-4 and y=8
Answer: x>2
Step-by-step explanation:
