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Eduardwww [97]
3 years ago
12

The molar mass of O2 is 32.0 g/mol.what mass,in grams,of O2 is required to react completely with 4.00 mol of Mg

Chemistry
2 answers:
Dahasolnce [82]3 years ago
7 0
The balanced equation for the reaction between Mg and O₂ is as follows
2Mg + O₂ --> 2MgO
stoichiometry between Mg and O₂ is 2:1
number of Mg reacted - 4.00 mol
if 2 mol of Mg reacts with 1 mol of O₂
then 4.00 mol of Mg requires - 1/2 x 4.00 = 2.00 mol of O₂
then the mass of O₂ required - 2.00 mol x 32.0 g/mol = 64.0 g
64.0 g of O₂ is required for the reaction 
katen-ka-za [31]3 years ago
3 0

Answer:

D on edge.

Explanation:

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Use the following balanced equation to answer the questions below.
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Answer:

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Explanation:

Let's consider the following balanced equation.

Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃

PART A

The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:

9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂

PART B

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