if you had a house with bot copper and zinc galvanized iron water pipes, which metal would be oxidized first? Why would this be
2 answers:
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Answer:
The density of the swimmer is 0.0342 lbm/in3.
This value makes sense as the density of the body is very similar to the water.
Explanation:
If the swimmers is floating, the weight of the swimmer must be equal to the upward buoyant force.
We can express the weight force as the product of density and volume of the swimmer.
Then
It makes sense as the density of the body is very similar to the water.
It is found that scuba diver’s can safely ascend up to 52.53 ft without Breathing out.
By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling or exhaling then
=patm+
= 101325+ρ
It is given that height is 125ft. Put the value of h in above formula:
h1 =125ft=38.1m
ρ=1.04g/mL=1040kg/
g=9.81
=101325Pa+388711.44
=490036.44Pa
=p atm =101325Pa
It is known that volume and pressure can be expressed as:
V*P=const.
where, V is volume and P is pressure.
Now,
=
=
=490036.44/101325
=4.84
Assume constant temperature
d of seawater = 1.04 g/mL; d of Hg = 13.5 g/mL.
now =p atm+
=490036.44Pa
V*p=const
where, V is volume and P is pressure.
Now,
=
=
=490036.44/X
=490036.44pa/(V2/V1) =326690.96Pa
=patm +p
=101325Pa+ρ
326690.96Pa=101325Pa+ρ
ρgh1 =151987.5-101325=225365.96Pa
ρ=1,04g/mL=1040kg/m3
g=9.81
=225365.96/ρ∗g
=225365.96 / 1040∗9.81
=22.09m= 72.47ft
ΔH=
=125-72.47
=52.53ft
So she can safely ascend up to 52.53 ft without Breathing out
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