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kolezko [41]
3 years ago
9

if you had a house with bot copper and zinc galvanized iron water pipes, which metal would be oxidized first? Why would this be

desirable?
Chemistry
2 answers:
kumpel [21]3 years ago
8 0
<span> Zinc is a strong reducing agent. Copper will be oxidized first. </span>
Mademuasel [1]3 years ago
6 0

Answer:

Zinc would oxidize faster, and this would be desirable because it forms a protective layer much like aluminum and this prevents further corrosion for a longer period of time.

Explanation:

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One symptom of carbon monoxide poisoning is the development of Mees lines on the fingernails and toenails.
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Mees' lines are white bands that form across your fingernails and are one of the symptoms of carbon monoxide poisoning.

Mees' lines are a sign that the growth of your nails temporarily stopped at one point. There are many causes to Mees' lines, and usually it indicates a toxicity. Carbon monoxide, along with other substances like arsenic, and selenium poisoning may cause them. 


3 0
3 years ago
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What is the most poisonous animal?
astraxan [27]

Answer:

That depends on what species it is

Explanation:

Like reptiles it is rattlesnakes

Spiders would be black widow

So it depends on the what species you what.

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3 years ago
At what point would a chemical bond form between two atoms.
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5 0
2 years ago
2. Chromium+oxygen - chromium(III) oxide <br>balanced​
sesenic [268]

Answer:

4Cr + 3O2 —> 2Cr2O3

Explanation:

Information from the question include:

Chromium + oxygen -> chromium(III) oxide

From the word equation given above, the equation can be written as follow:

Cr + O2 —> Cr2O3

The equation can be balance by doing the following:

There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 2 in front of Cr2O3 and 3 in front of O2 as shown below:

Cr + 3O2 —> 2Cr2O3

Now, we have 4 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 4 in front of Cr as shown below:

4Cr + 3O2 —> 2Cr2O3

Now the equation is balanced

3 0
3 years ago
What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
Vanyuwa [196]

Answer:

Mole fraction for solute = 0.1, or 10%

Molality = 6.24 mol/kg

Explanation:

22.3% by mass → In 100 g of solution, we have  22.3 g of HCOOH

Mass of solution = 100 g

Mass of solute = 22.3 g

Mass of solvent = 100 g - 22.3g = 77.7 g

Let's convert the mass to moles

22.3 g . 1mol/ 46 g = 0.485 moles

77.7 g. 1mol / 18 g = 4.32 moles

Total moles = 4.32 moles + 0.485 moles = 4.805 moles

Xm for solute = 0.485 / 4.805 = 0.100 → 10%

Molality → mol/ kg → we convert the mass of solvent to kg

77.7 g.  1 kg / 1000g = 0.0777 kg

0.485 mol / 0.0777 kg = 6.24 m

6 0
3 years ago
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