CH4 + 2 O2 ---> CO2 + 2 H2O Q = 891,6 kJ / mol CH4
1 mol CH4 = 16 g
16 g ---- 891,6 kJ
x g ----- 272 kJ
x = 272 kJ × 16 g / 891,6 kJ = 4,88 g
You must burn 4,88 g of CH4.
:-) ;-)
The SI unit for mass is Kilogram (kg).
We know, It's atomic formula = C4H10
Now, we know molar mass of C = 12 & H=1
so, it would be: 12*4+1*10 = 48+10 = 58
Molarity = number of moles/Volume (L). Solve for the number of moles in the initial solution (3.78M = n/0.3 L) and then use that amount of moles and the new volume (0.5 L) to solve for the new Molarity.
Answer:
I don't really ship anyone but if I had to pick it would probably be either kamijiro or tododeku.
Explanation:
