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Alekssandra [29.7K]
2 years ago
8

-

Chemistry
1 answer:
Dovator [93]2 years ago
3 0

Answer:

5 × 10^-4 L

Explanation:

The equation of the reaction is;

2KClO3 = 2KCl + 3O2

Number of moles of KClO3 = 13.5g/122.5 g / mol = 0.11 moles

From the stoichiometry of the reaction;

2 moles of KClO3 yields 3 moles of O2

0.11 moles of KClO3 yields 0.11 × 3/2 = 0.165 moles of oxygen gas

From the ideal gas equation;

PV= nRT

P= 85.4 × 10^4 KPa

V=?

n= 0.165

R= 8.314 J K-1 mol-1

T= 40+273 = 313K

V= 0.165 ×8.134 × 313/85.4 × 10^4

V=429.4/85.4 × 10^4

V= 5 × 10^-4 L

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3 years ago
How many grams of propane, C3H8, are needed to make 140 grams of water?
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Answer:

85.6 g

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140 g × 1 mol/18.02 g = 7.77 mol

Step 3: Calculate the moles of C₃H₈ needed to produce 7.77 moles of H₂O

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2 years ago
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