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Nastasia [14]
3 years ago
13

Sketch a horizontal cross section

Mathematics
1 answer:
Kryger [21]3 years ago
7 0

Answer:

Literally is flat two lines

Step-by-step explanation:

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2 ≤ q–1 = ???????????????????????????
crimeas [40]

Answer:

q ≥ 3

Step-by-step explanation:

add 1 to both sides and there you have your answer!

2 ≤  q-1

+1       +1

3 ≤  q

or

q ≥ 3

5 0
3 years ago
Read 2 more answers
What number will fill in the blank ...... 1/3 = (blank)/6
diamong [38]

Answer:

2

Step-by-step explanation:

1/3 = x/6

Equivalent fractions.

Multiply 3 by 2 for x

(1×2)/(3×2) = 2/6

3 0
2 years ago
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Given the Quadratic, determine the value of the discriminant.<br> 2x2 – 3x – 20 = 0
Andrews [41]
2x2-3x-20=0
4-3x-20=0
2-20=-16
-3x-16=0
-3x=16
x= -5.33333
I think i did it right. i hope this helps.
4 0
3 years ago
Differences between Prokaryotic and Eurkaryotic Cells?
dlinn [17]

Answer:

one ceel is heterosexual the other is fruity

3 0
2 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
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