Answer:
a) The continuous rate of growth of this bacterium population is 45%
b) Initial population of culture at t = 0 is 950 bacteria
c) number of bacterial culture contain at t = 5 is 9013 bacteria
Step-by-step explanation:
The number of bacteria in a culture is given by
n(t) = 950
a) rate of growth is
Bacteria growth model N(t) = no
Where r is the growth rate
hence r = 0.45
= 45%
b) Initial population of culture at t = 0
n(0) = 950
= 950
= 950 bacteria
c) number of bacterial culture contain at t = 5
n(5) = 950
= 950
= 9013.35
= 9013 bacteria
Answer:
A. No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means.
Step-by-step explanation:
No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means. The central limit theorem says that if we take a large sample (i.e., a sample of size n > 30) of any distribution with finite mean
and standard deviation
, then, the sample average is approximately normally distributed with mean
and variance
.
we'll do the same as before, turning the mixed fractions to improper and do the division, keeping in mind that is simply asking how many times 1⅕ goes into 8⅔.
![\bf \stackrel{mixed}{8\frac{2}{3}}\implies \cfrac{8\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{26}{3}}\\\\\\\stackrel{mixed}{1\frac{1}{5}}\implies \cfrac{1\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{6}{5}}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\cfrac{26}{3}\div \cfrac{6}{5}\implies \cfrac{26}{3}\cdot \cfrac{5}{6}\implies \cfrac{130}{18}\implies \cfrac{126+4}{18}\implies \cfrac{126}{18}+\cfrac{4}{18}\\\\\\\boxed{7+\cfrac{4}{18}}\implies 7\frac{4}{18}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cstackrel%7Bmixed%7D%7B8%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B8%5Ccdot%203%2B2%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B26%7D%7B3%7D%7D%5C%5C%5C%5C%5C%5C%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B1%7D%7B5%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%205%2B1%7D%7B5%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B6%7D%7B5%7D%7D%5C%5C%5C%5C%5B-0.35em%5D%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%5Ccfrac%7B26%7D%7B3%7D%5Cdiv%20%5Ccfrac%7B6%7D%7B5%7D%5Cimplies%20%5Ccfrac%7B26%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B5%7D%7B6%7D%5Cimplies%20%5Ccfrac%7B130%7D%7B18%7D%5Cimplies%20%5Ccfrac%7B126%2B4%7D%7B18%7D%5Cimplies%20%5Ccfrac%7B126%7D%7B18%7D%2B%5Ccfrac%7B4%7D%7B18%7D%5C%5C%5C%5C%5C%5C%5Cboxed%7B7%2B%5Ccfrac%7B4%7D%7B18%7D%7D%5Cimplies%207%5Cfrac%7B4%7D%7B18%7D%20)