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Ivenika [448]
3 years ago
12

Why do scientists need a standard system of measurement?

Physics
2 answers:
djyliett [7]3 years ago
7 0
The answer is so that everyone is measuring the same distance and counting that distance as the same everywhere. one example from real life why it is important to use standard units is the loss of the NASA mars orbiter. some people decided that the units were to be in metric and others thought that the units were in imperial (english) system. so the orbiter was lost.

let's eliminate some choices
A. to allow for consistientcy with measurement data:
not really, just make sure the instruments are accurate.

B. to use tools marked in customary units: this could be true because a custom is something that is accepted in a wide area and if it is standard, then it is customary so b is the answer

C. so they can keep measurement data secret: nope

D. to record with easier abbreviations: not really

the answer is B
yKpoI14uk [10]3 years ago
4 0


None of the given choices is worth much.

The scientific community ... ALL of them ... need a standard system
of measurement so that one scientist can understand the results of
another scientist's work. 

Science is not a bunch of recluse hermits each working alone in their
dusty dungeons.  Science is a  community.  Each scientist publishes
a very detailed description of what he tried and what results he got. 
If other scientists read it and get ideas of how they could chase
answers to the same questions, they can pick up where the first
scientist left off, build on his work, or go off in slightly different
directions. 

None of that can happen unless everyone precisely understands
everyone else's measurements.

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Consider a product with three components in​ series, with reliabilities of​ 0.90, 0.80, and 0.99 for components​ A, B, and​ C, r
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Answer:0.853

Explanation:

Given

Reliability of A is 0.90

Reliability of B is 0.80

Reliability of C is 0.99

B has a backup with reliability of 0.8

i.e. B has a component in parallel to it.

A,B& C is series.

B actual reliability is

R_b=1-\left ( 1-0.8\right )\left ( 1-0.8\right )

R_b=0.96

Thus R_{net} is given by

R_{net}=R_A\times R_B\times R_C

R_{net}=0.9\times 0.96\times 0.99

R_{net}=0.8553

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How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 162 mL of coffee at 94.6°C so that the r
Andre45 [30]

Answer:

The volume of water is 139 mL.

Explanation:

Due to the Law of conservation of energy, the heat lost by coffee is equal to the heat gained by the water, that is, the sum of heats is equal to zero.

Q_{coffee} + Q_{water} = 0\\Q_{coffee} = - Q_{water}

The heat (Q) can be calculated using the following expression:

Q=c \times m \times \Delta T

where,

c is the specific heat of each substance

m is the mass of each substance

ΔT is the difference in temperature for each substance

The mass of coffee is:

162mL.\frac{0.997g}{mL} = 162g

Then,

Q_{coffee} = - Q_{water}\\c_{c} \times m_{c} \times \Delta T_{c} = -c_{w} \times m_{w} \times \Delta T_{w}\\m_{c} \times \Delta T_{c} = -m_{w} \times \Delta T_{w}\\m_{w} = \frac{m_{c} \times \Delta T_{c}}{-\Delta T_{w}} \\m_{w}=\frac{162g \times (62.5 \°C - 94.6 \°C ) }{-(62.5 \°C - 25.0 \°C)} \\m_{w} = 139 g

The volume of water is:

139g.\frac{1mL}{0.997g} =139mL

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4 years ago
2. A car traveling 300 miles in 5 hours is an example of
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